1、 1/5 鄂州市 2018 年初中毕业生学业考试 数学答案解析 第卷 一、选择题 1.【答案】B 2.【答案】D 3.【答案】A 4.【答案】B 5.【答案】C 6.【答案】A 7.【答案】A 8.【答案】A 9.【答案】B 10.【答案】A 第卷 二、填空题 11.【答案】232a 12.【答案】3 13.【答案】12cm 14.【答案】10 x 或2x 15.【答案】22 3或23 16.【答案】1 或 2 三、解答题 17.【答案】解:原式32xx(或写成32xx).3,0,2x ,当2x 时,原式32.18.【答案】解:(1)证明:90DAB,E为DB中点,2/5 12AEDB.EF,
2、分别是DBBC,的中点,12EFCDEFCD,.DBDCAEEF,.(2)AEEFAFAE,AEF为正三角形,60AEF,=2.2=60.EDEAADBAEBEFCDCDBBEF,19.【答案】解:(1)0.304ab,补图略.(2)1800.350.20=99(人),估计有学生 99 人.(3)列表或画树状图略.一共有12种等可能的结果,所选两人都是甲班学生共有3种结果,则所求概率31124P.20.【答案】解:(1)证明:2=10k,无论k为何值时,方程都有实数根.(2)212121212223324222362422 33365140 xxkx xkkx xxxkkkkk,解得1272.
3、kk,1212.11=8829.22kkSx x 菱形,21【答案】解:(1)75304515120.BACCB,(2)过C作CHAB于H.6030.HBCHCB,设BHx,则3CHx,3/5 3402031266 203160 220 6133.8.xxxACCHx,AC的长为 133.8 海里.22.【答案】解:(1)连接OA.ADBACBACBOACPABADBOACPAB,BC为直径,9090CABPAO,PA为O的切线.(2)903tantan.46810.34CABABADBACBACABACBCPABACBPPPABPCAPBPAABPAPCAC ,=,=,设3PBx,则4PAx
4、,163xPC,163103xx,解得307x,90.7PB (3)连接OD,交AC于点F,224.13532.290241.11525.22CDEADCDODACCFAFOCOBOFABDFBDCDFACDFCF DFEFEFSCF DF,23.【答案】解:(1)4020200201000.yxx (2)222020201 0002014002000020354500.Wxyxxxxx 4/5 当35x 时,max4500W元.(3)依题意得2201400200004000201000320 xxx,解得30403034.34xxx,答:销售单价应定在30元至34元之间.24.【答案】解:(
5、1)当4x 时,52m,05164232abcabcc ,解得12132abc ,2131,2.22yxxM,(2)作PEy轴交AB于点E,设213,22P xxx,则11,22E xx,2214121111352222253125.4216PABSPExxxx 当32x 时,max12516S,此时点 P 的坐标为315,.28(3)1,0,3,01,2ADM,AMD为等腰直角三角形,90AMD,90.QMNAMDMQNQMQN,作NGx轴于点G,MHx轴于点H,设213,022N nnnQ m,5/5 当点Q在MN左侧时,则213=1222nnmnm,解得5133mmnn ,5,01,0Q,;当点Q在MN右侧时,则213=1222nnmmn,解得7151mmnn,7,0.Q 综上,点 5,01,07,0.Q,