双基限时练(六)一、选择题1等差数列an中,a4a512,那么它前8项之和等于()A12 B24C36 D48解析S848.答案D2已知等差数列an的前n项和为Sn,若S24,S412,则S8等于()A36 B40C48 D24解析由S24,S412,S4S28.S2,S4S2,S6S4,S8S6成等差数列,S8444162440.答案B3已知在等差数列an中,S1326,S1050,则公差d为()A2 B2C4 D4解析由S1326,知a72,又S1050,得a4a710,得a48,又a7a43d,d2.答案B4已知数列an的前n项和Snn29n,第k项满足5ak8,则k的值为()A9 B8C7 D6解析Snn29n,an为等差数列,akSkSk1k29k(k1)29(k1)2k192k10.由5ak8,得k0.a3a4a2a522,又a3a4117,a3,a4是方程x222x1170的两个根又公差d0,a3a4,a39,a413.an4n3.(2)由(1)知,Snn142nn,bn.b1,b2,b3.bn是等差数列,2b2b1b3,2c2c0,c(c0舍去)