资源描述
一.选择结构
'-------------------------------------------------
'题目:编写函数fun,函数的功能是:根据一个百分制
' 成绩mark(整数),显示对应五级制的评定。条件如下:
' mark大于等于90显示"优秀"
' mark小于90且大于等于80显示"良好"
' mark小于80且大于等于70显示"中等"
' mark小于70且大于等于60显示"及格"
' mark小于60显示"不及格"
' 要求使用IF语句来实现。
'-------------------------------------------------
Private Function fun(mark As Integer) As String
'**********Program**********
If mark >= 90 Then
fun = "优秀"
ElseIf mark >= 80 Then
fun = "良好"
ElseIf mark >= 70 Then
fun = "中等"
ElseIf mark >= 60 Then
fun = "及格"
Else
fun = "不及格"
End If
'********** End **********
End Function
Private Sub Form_Load()
Show
Print fun(90)
End Sub
'-------------------------------------------------
'题目:编写函数fun,函数的功能是:
判断一个字符是: 字母字符、数字字符还是其他字符,并做相应的显示。
' 字母字符显示字符串"字母"' 数字字符显示字符串"数字"
' 其他字符显示字符串"其他" ' 要求使用select语句来实现
'-------------------------------------------------
Private Function fun(n As String) As String
'**********Program**********
Select Case n
Case "A" To "Z", "a" To "z"
fun = "字母"
Case "0" To "9"
fun = "数字"
Case Else
fun = "其他"
End Select
'********** End **********
End Function
Private Sub Form_Load()
Show
Print fun("A")
Print fun("9")
Print fun("&")
End Sub
二.一般循环
'-------------------------------------------------
'题目:(事件)双击窗体。
' (响应)求出100~200之间,能被5整除,但不能被3整除的数。输出这些数
并求所有数之和,存入变量中SUM中。 输出sum 应为 2100
'-------------------------------------------------
Private Sub Form_dblClick()
Dim sum As Integer
sum = 0
'********** Program *********
Dim i As Integer
For i = 100 To 200
If ((i Mod 5) = 0) And ((i Mod 3) <> 0) Then
Print (CStr(i))
sum = sum + i
End If
Next
'********** End *************
Print sum
End Sub
'-------------------------------------------------
'题目:(事件)单击窗体。 输出L 应为 46189
' (响应)求10~20之间所有素数的乘积并输出在窗体上。将结果存入变量L中。
'-------------------------------------------------
Private Sub Form_Click()
Dim l As Long
'******* Program ********
Dim i As Integer
Dim j As Integer
Dim b As Boolean
l = 1
b = False
For i = 10 To 20
For j = 2 To i - 2
If i Mod j = 0 Then
b = True
End If
Next
If b = False Then
l = l * i
End If
b = False
Next
Print Str(l)
'********* End ***********
End Sub
'-------------------------------------------------
'题目:(事件)单击窗体。
' (响应)编写程序求10×11×12+11×12×13+…+15×16×17的结果,
' 并将结果输出到窗体上。将结果存入变量M中 输出M 应为 15390
'-------------------------------------------------
Private Sub Form_Click()
Dim m As Long
'******** Program *************
Dim i, j As Integer
Dim s As Long
For i = 10 To 15
s = 1
For j = i To i + 2
s = s * j
Next
m = m + s
Next
Print (CStr(m))
'************ End ***********
End Sub
'-------------------------------------------------
'题目:(事件)单击窗体。
' (响应)在窗体上打印数列2/1,3/2,5/3,8/5,13/8… 的前10项,并求其和,
将和保存在变量s中 输出:
'-------------------------------------------------
Private Sub Form_Click()
Dim s As Single
'******** Program ***********
Dim i, j, k, m As Integer
s = 0
i = 2
j = 1
For k = 1 To 10
s = s + i / j
m = j
Print (CStr(i)) & "/" & CStr(j)
j = i
i = i + m
Next
'********* End ****************
End Sub
'-------------------------------------------------
'题目:编写函数fun其功能是:根据整型形参m,计算如下公式的值:
' y=1+1/3+1/5+1/7+...+1/(2m+1) 例如:若m=9,则应输出:2.133255
'-------------------------------------------------
Private Function fun(m As Integer) As Single
Dim y As Double
'********** Program *********
Dim y As Double
Dim i As Integer
y = 1
For i = 1 To m
y = y + 1 / (2 * i + 1)
Next
fun = y
'********** End *************
End Function
Private Sub Form_Load()
Show
Print fun(9)
End Sub
'-------------------------------------------------
'题目:函数fun其功能是:根据整型形参m,计算如下公式的值:y=1/2+1/4+1/6+...+1/2m
' 例如:若m=9,则应输出:1.41448412698413
'-------------------------------------------------
Private Function fun(m As Integer) As Double
'********** Program *********
Dim y As Double
Dim i As Integer
For i = 1 To m
y = y + 1 / (2 * i)
Next
fun = y
'********** End *************
End Function
Private Sub Form_Load()
Show
Print fun(9)
End Sub
'-------------------------------------------------
'题目: (事件)单击窗体。
' (响应)已知sum=1-1/4+1/9-1/16+1/25...-1/100, 输出 sum 应为 0.8179622
' 请将sum结果值输出到窗体上。 使用for...next语句完成程序
'-------------------------------------------------
Private Sub Form_Click()
Dim sum As Single
'***************** Program **************
Dim i As Integer
for i = 1 to 10
sum = sum + (-1) ^ (i - 1) /(i*i)
next
Print sum
'*************** End *************************
End Sub
三.级数
'-------------------------------------------------
'题目: (事件)单击窗体。
' (响应)已知sum=1/2!-1/4!+1/6!-1/8!+1/10!,请将sum结果值输出到窗体上。
' 使用do while...loop语句完成程序 输出sum 应为 0.4596977
'-------------------------------------------------
Private Sub Form_Click()
Dim p As Long 'p变量存放阶乘的值
Dim sum As Single
'***************** Program **************
Dim i As Integer
Dim n As Integer
i = 1
p = 1
Do While i <= 10
p = p * i
If i Mod 2 = 0 Then
n = n + 1
sum = sum + (-1) ^ (n - 1) / p
End If
i = i + 1
Loop
Print sum
'*************** End *************************
End Sub
'-------------------------------------------------
'题目:(事件)单击窗体。
' (响应)已知S=1+1/4+1/9+1/16+1/25+…+1/100,结果输出在窗体上。输出s 应为 1.291286
'-------------------------------------------------
Private Sub Form_Click()
Dim s As Single
'************* Program **************
Dim i As Integer
s = 0
For i = 1 To 10
s = s + 1 / (i ^ i)
Next
Print (s)
'************* End **************
End Sub
'-------------------------------------------------
'题目: (事件)单击窗体。
' (响应)求sum=1+1+2+3+5+8+13+...+144的和,请将sum结果值输出到窗体上。
使用 do...loop语句完成程序 输出sum 应为 376
'-------------------------------------------------
Private Sub Form_Click()
Dim sum As Long
'***************** Program **************
Dim i As Integer
Dim s1 As Integer
Dim s2 As Integer
i = 1
s1 = 1: s2 = 1
Sum = Sum + s1 + s2
Do
If s2 = 144 Then
Exit Do
End If
s1 = s1 + s2
s2 = s1 + s2
Sum = Sum + s1 + s2
Loop
Print Sum
'*************** End *************************
End Sub
'-------------------------------------------------
'题目:编写函数fun其功能是:根据整型形参m,计算如下公式的值:
' y=1/5+1/6+1/7+1/8+1/9+1/10...+1/(m+5) 例如:若m=9,则应输出:1.168229
'要求:函数中用到的中间变量必须声明为Single类型。
'-------------------------------------------------
Private Function Fun(m As Integer) As Single
'********** Program *********
Dim y As Double
Dim i As Integer
For i = 0 To m
y = y + 1 / (i + 5)
Next
Fun = y
'********** End *************
End Function
Private Sub Form_Load()
Show
Print Fun(9)
End Sub
四.数字关系
'-------------------------------------------------
'题目:编写函数fun其功能是:
判断一个整数w的各位数字平方之和能否被5整除 , 可以被5整除则返回1 , 否则返回0
'-------------------------------------------------
Private Function fun(w As Integer) As Boolean
'********** Program *********
Dim k As Integer, s As Integer
Do
s = s + (w Mod 10) * (w Mod 10)
w = Int(w / 10)
Loop While w <> 0
If s Mod 5 = 0 Then
k = 1
Else
k = 0
End If
fun = k
'********** End *************
End Function
Private Sub Form_Load()
Show
Print fun(50) '输出True
Print fun(51) '输出False
End Sub
'-------------------------------------------------
'题目:(事件)双击窗体。
' (响应)写程序解决百钱买百鸡问题:公鸡3元1只,母鸡5元1只,小鸡一元3只,
怎样用100元买100只鸡。
把结果输出到窗体上。将答案数存放在变量N中。 输出
'-------------------------------------------------
Private Sub Form_dblClick()
Dim n As Integer
n = 0
'******** Program *******
Dim i, j, k As Integer
For i = 1 To 20 '母鸡
For j = 1 To 33 '公鸡
For k = 3 To 100 '小鸡
If ((k Mod 3) = 0) And ((i * 5 + j * 3 + k / 3) = 100) And ((i + j + k) = 100) Then
Print (CStr(i))
Print (CStr(j))
Print (CStr(k))
n = n + 1
End If
Next
Next
Next
'************ End ***********
End Sub
'-------------------------------------------------
'题目: (事件)单击窗体。
' (响应)输出所有的三位数,它满足该数中有某两位为相同的数,
且该数是一个完全平方数。
' 求出所有这些数的和,并将结果存入变量SUM中。 输出
'-------------------------------------------------
Private Sub Form_Click()
Dim sum As Integer
'***************** Program **************
dim a as integer,b as integer
dim b3 as integer,b2 as integer,b1 as integer
for a=10 to 31
b=a*a
b3=b\100
b2=(b\10) mod 10
b1=b mod 10
if b1=b2 or b1=b3 or b2=b3 then
? a,b
sum=sum+b
end if
next a
Print sum
'*************** End *************************
End Sub
'-------------------------------------------------
'题目:(事件)单击窗体。
' (响应)求出1000-9999之间具有如下特点的四位数字,
它的平方根恰好就是它中间的两位数字,
例如,2500开平方为50,恰为2500的中间两位, 输出
找出所有这样的四位数。并求出所有这样的数的和存入SUM中
'-------------------------------------------------
Private Sub Form_Click()
Dim sum As Integer
sum = 0
'******** Program *******
Dim i As Integer
Dim j As Integer
For i = 1000 To 9999
j = Val(Mid(Trim(Str(i)), 2, 2))
If j ^ 2 = i Then
Print i,
sum = sum + i
End If
Next
'********** End **********
End Sub
'-------------------------------------------------
'题目: (事件)单击窗体。
' (响应)求一个数,它除3余2,除5余3,除7余2,
' 请将满足上面条件的最小数保存到sum变量中。 输出 sum 应为23
' 使用for...next语句完成程序
'-------------------------------------------------
Private Sub Form_Click()
Dim sum As Integer
'***************** Program **************
Dim i As Integer
For i = 2 To 1000
If i Mod 3 = 2 And i Mod 5 = 3 And i Mod 7 = 2 Then
Print i
Exit For
End If
Next i
sum = i
'*************** End *************************
End Sub
五.递推
'-------------------------------------------------
'题目:编写函数fun,函数的功能是:
当x的初值为10,每年增长率为百分之一,计算多少年以后x的值能达到y,
'并显示所需年数的值(变量名必须为n)。
' 要求使用Do ... Loop Until语句来实现。 当y为15时, n应该为41
'-------------------------------------------------
Private Function fun(y As Single) As Long
Dim x As Single, n As Long
'**********Program**********
x = 10
n = 0
Do While x < y
x = x * 1.008
n = n + 1
Loop
fun = n
'********** End **********
End Function
Private Sub Form_Load()
Show
Print fun(15)
End Sub
'-------------------------------------------------
'题目:已知,猴子吃一堆桃子,每天吃桃子总数的一半多一个。到第n天时,桃子只剩一个。
编写函数fun,函数的功能是: '求出开始桃子的数量并显示。如:' n为7时,则显示"190"
'要求使用For语句来实现。 要求使用Do Until ... Loop语句来实现
'-------------------------------------------------
Private Function fun(n As Long) As String
'**********Program**********
x = 1
i = 1
Do Until i = n
x = (x + 1) * 2
i = i + 1
Loop
fun = x
'********** End **********
End Function
Private Sub Form_Load()
Show
Print fun(7)
End Sub
'---------------------------------------------------------------
'题目:用迭代法求某个数的平方根。 已知求平方根的迭代公式如图:
'算法思想:对于一个问题的求解x,可由给定的一个初值x0,根据某一
' 迭代公式得到一个新的值x1,这个新值x1比初值x0更接近要求的值x;
' 再以新值作为初值,即:x1→x0,重新按原来的方法求x1,重复这一过和
' 直到|x1-x0|<ε(某一给定的精度为0.00001)。此时可将x1作为问题的解。
'-----------------------------------------------------------------------
Private Function Fsqrt(a As Single) As Single
'********** Program *********
Dim x0 As Single, x1 As Single
x0 = a / 2 '迭代初值
x1 = 0.5 * (x0 + a / x0)
Do
x0 = x1 '为下一次迭代作准备
x1 = 0.5 * (x0 + a / x0)
Loop While Abs(x1 - x0) > 0.00001
Fsqrt = x1
'********** End *************
End Function
Private Sub Form_Load()
Show
Print Fsqrt(45) ' 当a为45 时应输出6.708204
End Sub
六.数组
'-------------------------------------------------
'题目:求二维数组中最大元素及其所在的行和列并将最大值存入变量Max中,
将最大值的行位置存入row中,列位置存入变量column中. 输出:
'-------------------------------------------------
Private Sub Form_Load()
Show
Dim a(2, 3) As Integer
Dim max As Integer, row As Integer, column As Integer
a(1, 1) = 34: a(1, 2) = 34: a(1, 3) = 43: a(2, 1) = 34: a(2, 2) = 78: a(2, 3) = 12
'********** Program *********
Dim i As Integer, j As Integer
max = a(1, 1): row = 1: column = 1
For i = 1 To 2
For j = 1 To 3
If a(i, j) > a(row, column) Then
max = a(i, j) : row = I : column = j
End If
Next j
Next i
Print "最大元素是"; max
Print "在第" & row & "行,"; "第" & column & "列"
'********** End *************
End Sub
'-------------------------------------------------
'题目:应用选择法对数组A按升序排列
'基本思想:
' 1)对有n个数的序列(存放在数组a(n)中),从中选出最小的数,与第1个数交换位置;
' 2)除第1 个数外,其余n-1个数中选最小的数,与第2个数交换位置;
' 3)依次类推,选择了n-1次后,这个数列已按升序排列。
' 输出排序前后数组数据,验证结果
'-------------------------------------------------
Private Sub Sort(ByRef a() As Integer, n As Integer)
'********** Program *********
Dim i, j, imin, temp As Integer
For i = 1 To n - 1
imin = i
For j = i + 1 To n
If a(imin) > a(j) Then imin = j
Next j
temp = a(i)
a(i) = a(imin)
a(imin) = temp
Next i
'********** End *************
End Sub
Private Sub Form_Load()
Show
Dim i As Integer
Dim arr(10) As Integer
Randomize
Print "排序前:"
For i = 1 To 10
arr(i) = Int(10 * Rnd + 1) : Print arr(i);
Next
Print
Sort arr, 10
Print "排序后:"
For i = 1 To 10
Print arr(i);
Next
End Sub
'-------------------------------------------------
'题目:(事件)单击窗体。
' (响应)生成一个一维数组(10个数组元素依此为:15、23、72、43、96、23、3、65、88、17),
' 写程序求出这个数组中的最大值、最小值和平均值,并输出在窗体上。
' 将最大值,最小值,平均值分别存入变量Max,Min,Aver中 输出Max为96,Min为3,Aver为44
'-------------------------------------------------
Private Sub Form_Click()
Dim max, min, aver As Integer
'*********** Program **********
Dim a()
Dim i, s As Integer
a = Array(15, 23, 72, 43, 96, 23, 3, 65, 88, 17)
max = a(0)
min = a(0)
s = 0
For i = 0 To 9
If a(i) > max Then
max = a(i)
End If
If a(i) < min Then
min = a(i)
End If
s = s + a(i)
Next
aver = Int(s / 10)
Print max, min, aver
'********** End **************
End Sub
七.杂项
'-------------------------------------------------
'题目:对字符串进行加密处理。 加密过程:
将每个字母C减一序数K=5,即 c=chr(Asc(c)- k),这时 "Z"→"U", "z"→"u","Y"→"T"…
当加序数后的字母小于"A"或"a"则 c=Chr(A
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