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单击此处编辑母版标题样式,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,*,*,七年级数学下册,(,华师版,),第9章多边形,91三角形,91.2三角形的内角和与外角和,1,三角形的内角和等于,2,直角三角形的两个锐角,_,3,三角形的外角的性质:,(1),三角形的一个外角等于与它,的两个内角的和;,(2),三角形的一个外角大于任何一个与它,的内角,4,三角形的外角和等于,180,互余,不相邻,不相邻,360,1,在,ABC,中,,,若,A,50,,,B,70,,,则,C,(,),A,50,B,60,C,70,D,80,2,在,ABC,中,,,A,:,B,:,C,3,:,4,:,5,,,则,C,等于,(,),A,45,B,60,C,75,D,90,B,C,3,如图,,,在,ABC,中,,,B,67,,,C,33,,,AD,是,ABC,的角平分线,,,则,CAD,的度数为,4,如图,,,在,ABC,中,,,ACB,90,,,CD,AB,于,D,,,若,B,40,,,则,A,,,1,5,如图,,,AD,交,BC,于点,O,,,A,C,90,,,若,B,25,,,则,D,_,_,度,40,50,40,25,解:,C,50,解:,B,80,,,C,60,解:,A,15,,,B,75,,,C,90,7,如图,,,图中,1,的大小等于,(,),A,40,B,50,C,60,D,70,8,如图,,,下列各式正确的是,(,),A,A,2,1,B,1,2,A,C,2,1,A,D,1,A,2,D,B,9,直接根据图示填空:,(1),;,(2),;,(3),100,60,35,10,如图,,,直线,a,b,,,直线,AC,分别交,a,,,b,于点,B,,,C,,,直线,AD,交,a,于点,D,,,若,1,20,,,2,65,,,则,3,_,.,11,如图,,,在锐角三角形,ABC,中,,,CD,,,BE,分别是,AB,,,AC,边上的高,,,且,CD,,,BE,交于点,P,,,若,A,70,,,则,BPC,12,如图,,,A,B,C,D,E,F,的度数为,_,_,45,110,360,C,C,15,在,ABC,中,,,若,A,,,B,,,C,满足,B,A,C,B,,,则,B,_,_,度,16,将一副三角尺按如图所示的方式放置,,,使含,30,角的三角尺的短直角边和含,45,角的三角尺的一条边重合,,,则,1,的度数是,_,_,60,75,17,如图,,,直线,a,b,,,则,BAC,_,_,,,若作,BH,AC,于,H,,,则,ABH,_,_,18,如图,,,B,处在,A,处的南偏西,45,方向,,,C,处在,A,处的南偏东,15,方向,,,C,处在,B,处的北偏东,80,方向,,,则,ACB,的度数是,_,_,20,70,85,19,如图,,,AD,平分,CAE,,,B,35,,,DAE,60,,,试求,ACB,的度数,解:,AD,平分,CAE,,,CAE,2,DAE,,,DAE,60,,,CAE,60,2,120,,,BAC,180,120,60,,,B,35,,,ACD,B,BAC,35,60,95,20,如图,,,在,ABC,中,,,已知,AD,是角平分线,,,B,66,,,C,54.,(1),求,ADB,和,ADC,的度数;,(2),若,DE,AC,于点,E,,,求,ADE,的度数,解:,(,1),BAC,180,B,C,,,又,B,66,,,C,54,,,BAC,180,66,54,60,,,AD,平分,BAC,,,BAD,30,,,ADB,180,66,30,84,,,ADC,180,ADB,96,(,2),DE,AC,,,DEA,90,,,由,(,1),知,DAC,30,,,ADE,90,30,60,21,如图,,,ABC,内一点,O,,,1,25,,,2,28,,,BAC,55.,(1),求证:,BOC,BAC,;,(2),求,BOC,的度数,解:,(,1),连接,AO,并延长交,BC,于,D,点,,,BOD,是,AOB,的外角,,,BOD,3,,,同理,COD,4,,,BOD,COD,3,4,,,即,BOC,BAC,(,2),BOD,是,AOB,的外角,,,BOD,1,3,,,同理,COD,4,2,,,BOC,BOD,COD,1,3,4,2,1,BAC,2,108,22,如图,,,将,ABC,沿,EF,折叠,,,使点,C,落到点,C,处,,,试探究,1,,,2,与,C,的关系,解:,1,2,2,C,,,理由如下:连接,CC,,,则由折叠知,ECF,ECF,,,1,ECC,ECC,,,2,FCC,FCC,,,1,2,ECC,ECC,FCC,FCC,2,C,
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