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电大微积分初步期末复习资料小抄
一、填空题
⒈函数的定义域是 .
答案:
⒉函数的间断点是= .答案:
⒊曲线在点的斜率是 .答案:
⒋若,则 .
答案:
⒌微分方程的阶数是 2 .
6.函数, .答案:
7.函数在处连续,则= 2 .
8.曲线在点的斜率是 .答案:
9. .答案:4
10.微分方程的阶数是 .答案:2
11.函数的定义域是 .答案:
12.若,则 .答案:2
13.已知,则= .答案:
14.若 .答案:
15.微分方程的阶数是 3 .
16.函数的定义域是(-2,-1)∪(-1,4】.
17.若,则 2.
18.曲线在点处的切线方程是_y=x+1__.
19. 0 .
20.微分方程的特解为 y=e的x次方 .
21.函数的定义域是 .
22.若函数,在处连续,则 2 .
23.曲线在点处的斜率是 .
24. .
25.微分方程满足初始条件的特解为 .
26.函数的定义域是 .
答案:
27.函数的定义域是 .
答案:
28.函数的定义域是 .
答案:
29.函数,则 .
答案:
30.函数,则 .
答案:
31.函数,则 .
答案:
32.函数的间断点是 .
答案:
33. .
答案: 1
34.若,则 .
答案: 2
35.若,则 .
答案:
36.曲线在点的斜率是.
37.曲线在点的切线方程是.
38.曲线在点处的切线方程是.
39..
40.若y = x (x – 1)(x – 2)(x – 3),则(0) = -6 .
41.已知,则=.
42.已知,则=.
43.若,则-2 .
44.函数在区间内单调增加,则a应满足 大于零
45.若的一个原函数为,则 。
答案:` (c为任意常数)
46若的一个原函数为,则 。
答案:
47若,则 .
答案:
48若,则 .
答案:
49.若,则 .
答案:
50.若,则 .
答案:
51. .
答案:
52. .
答案:
53.若,则 .
答案:
10.若,则 .
答案:
54.
答案:
55.
答案:2
56.已知曲线在任意点处切线的斜率为,且曲线过,则该曲线的方程是 。
答案:
57.若 答案:4
58.由定积分的几何意义知,= 。答案:,它是1/4半径为a的圆的面积。
59. 答案:0
60.= . 答案:
61.微分方程的特解为 . 答案:1
62.微分方程的通解为 .答案:
63.微分方程的阶数为 .
答案:2
64.函数的定义域是___且 。
65.函数+的定义域是_ _。
66.设=,则=___0____。
67.函数,则___ 。
68._______ 。
69.设,则_______。
70.曲线在点的切线方程是______ 。
71.函数在区间__________内是单调减少的。
72.函数的单调增加区间是 .
73.若,则 .
74._______。
75. .
76. 0 .
77. 2 .
78.微分方程的阶数是 二阶 .
二、单项选择题
⒈设函数,则该函数是(偶函数).
⒉若函数,则().
⒊函数在区间是(先减后增)
⒋下列无穷积分收敛的是().
⒌微分方程的通解是()
6.函数的定义域(且).
7.若函数,则( 1 ).
8.函数在区间是(先减后增)
9.下列无穷积分收敛的是().
10.下列微分方程中为一阶线性微分方程的是()
11.设函数,则该函数是(偶函数).
12.当=( 2 )时,函数,在处连续.
13.微分方程的通解是( )
14.设函数,则该函数是(偶函数).
15.当(2)时,函数,在处连续.
16.下列结论中(在处不连续,则一定在处不可导. )正确.
17.下列等式中正确的是().
18.微分方程的阶数为(3)
19.设,则()
20.若函数f (x)在点x0处可导,则(,但 )是错误的.
21.函数在区间是(先减后增) 22.若,则().
23.微分方程的阶数为(3)
24.设函数,则该函数是(偶函数).
25.设函数,则该函数是(奇函数).
26.函数的图形是关于(坐标原点)对称.
27.下列函数中为奇函数是( ).
28.函数的定义域为(且).
29.函数的定义域是( ).
30.设,则( )
31.下列各函数对中,(,)中的两个函数相等.
32.当时,下列变量中为无穷小量的是( ). 答案:C
33.当( 1 )时,函数,在处连续.
34.当( 3 )时,函数在处连续.
35.函数的间断点是( )
36.函数在区间是(先减后增)
37.满足方程的点一定是函数的(驻点).
38.若,则=(-1 ).
39.设是可微函数,则( ).
40.曲线在处切线的斜率是( ).
41.若,则( ).
42.若,其中是常数,则( ).
43.下列结论中(在处连续,则一定在处可微.)不正确.
44.若函数f (x)在点x0处可导,则(,但)是错误的.
45.下列结论正确的有(x0是f (x)的极值点,且(x0)存在,则必有(x0) = 0).
46.下列等式成立的是().
47.若,则().
48.若,则( ).
49.以下计算正确的是( )
50.( )
51.=( ).
52.如果等式,则( )
53.在切线斜率为2x的积分曲线族中,通过点(1, 4)的曲线为( y = x2 + 3 ).
54.若= 2,则k =( 1 ).
55.下列定积分中积分值为0的是( ).
56.设是连续的奇函数,则定积分( 0 )
57.( ).
58.下列无穷积分收敛的是( ).
59.下列无穷积分收敛的是( ).
60.下列微分方程中,( )是线性微分方程.
61.微分方程的通解为( ).
62.下列微分方程中为可分离变量方程的是( )
63.函数y=的定义域是((-2,2])。
64.设,则( )。
65.函数的图形关于(轴)对称.
66、当时,变量( )是无穷小量.
67.函数 在x = 0处连续,则k = (-1).
68.曲线在点(1,0)处的切线方程是( )。
69.若,则( )。
70.函数在区间内满足(单调上升 ).
71.函数y=x2-2x+5在区间 (0,1) 上是(单调减少 )。
72.下列式子中正确的是( )。
73.以下计算正确的是( )
74.若,则( ).
75.( )。
76.下列定积分中积分值为0的是( ).
77.微分方程的通解是( )。
三、计算题(本题共44分,每小题11分)
⒈ 计算极限.
解
⒉ 设,求.
解
3.计算不定积分
解
4.计算定积分
解
5.计算极限.
解
6. 设,求.
解
7.计算不定积分
解 =
8.计算定积分
解
9.计算极限.
解
10.设,求.
解
11.计算不定积分
解 =
12.计算定积分
解
12.计算极限.
解:原式
13.设,求.
解:
14.计算不定积分
解:=
15.计算定积分
解:
16.计算极限.
解:原式
17.设,求.
解:
18.计算不定积分
解:=
19.计算定积分
解:
20.计算极限.
解
21.计算极限
解
22.
解
23.计算极限
解
24.计算极限.
解
25.计算极限.
解
26.计算极限.
解
27.设,求.
解
28.设,求.
解
29.设,求.
解
30.设,求.
解,
31.设,求.
解
32.设是由方程确定的隐函数,求.
解
33.设是由方程确定的隐函数,求.
解
34.设,求.
解
35.
解 利用分部积分法
设,,则,
36.
解 利用分部积分法
设,,则,
四、应用题
1.用钢板焊接一个容积为4的底为正方形的无盖水箱,已知钢板每平方米10元,焊接费40元,问水箱的尺寸如何选择,可使总费最低?最低总费是多少?
解:设水箱的底边长为,高为,表面积为,且有
所以
令,得,
因为本问题存在最小值,且函数的驻点唯一,所以,当时水箱的表面积最小. 此时的费用为 (元).
2.欲做一个底为正方形,容积为62.5立方米的长方体开口容器,怎样做法用料最省?
解:设底边的边长为,高为,容器的表面积为,由已知,
令,解得是唯一驻点,易知是函数的极小值点,此时有,所以当,时用料最省.
3. 欲用围墙围成面积为216平方米的一成矩形的土地,并在正中用一堵墙将其隔成两块,问这块土地的长和宽选取多大尺寸,才能使所用建筑材料最省?
解:设土地一边长为,另一边长为,共用材料为
于是 =3
令得唯一驻点(舍去)
因为本问题存在最小值,且函数的驻点唯一,所以,当土地一边长为,另一边长为18时,所用材料最省.
4. 欲做一个底为正方形,容积为108立方米的长方体开口容器,怎样做法用料最省?
解:设底边的边长为,高为,用材料为,由已知
令,解得是唯一驻点,
且,
说明是函数的极小值点,所以当,时用料最省。
5.欲用围墙围成面积为216平方米的一成矩形的土地,并在正中用一堵墙将其隔成两块,问这块土地的长和宽选取多大尺寸,才能使所用建筑材料最省?
解 设土地一边长为,另一边长为,共用材料为
于是 =3
令得唯一驻点(舍去)
五、证明题(本题5分)
1、函数在(是单调增加的.
证 只需证明当时,有
因为
当时,,即有
所以,当时,是单调增加的。
1、证明等式。
证明:显然是偶函数,是奇函数,
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