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第二章 简单线性回归模型
2.1
(1) ①首先分析人均寿命与人均GDP的数量关系,用Eviews分析:
Dependent Variable: Y
Method: Least Squares
Date: 12/27/14 Time: 21:00
Sample: 1 22
Included observations: 22
Variable
Coefficient
Std. Error
t-Statistic
Prob.
C
56.64794
1.960820
28.88992
0.0000
X1
0.128360
0.027242
4.711834
0.0001
R-squared
0.526082
Mean dependent var
62.50000
Adjusted R-squared
0.502386
S.D. dependent var
10.08889
S.E. of regression
7.116881
Akaike info criterion
6.849324
Sum squared resid
1013.000
Schwarz criterion
6.948510
Log likelihood
-73.34257
Hannan-Quinn criter.
6.872689
F-statistic
22.20138
Durbin-Watson stat
0.629074
Prob(F-statistic)
0.000134
有上可知,关系式为y=56.64794+0.128360x1
②关于人均寿命与成人识字率的关系,用Eviews分析如下:
Dependent Variable: Y
Method: Least Squares
Date: 11/26/14 Time: 21:10
Sample: 1 22
Included observations: 22
Variable
Coefficient
Std. Error
t-Statistic
Prob.
C
38.79424
3.532079
10.98340
0.0000
X2
0.331971
0.046656
7.115308
0.0000
R-squared
0.716825
Mean dependent var
62.50000
Adjusted R-squared
0.702666
S.D. dependent var
10.08889
S.E. of regression
5.501306
Akaike info criterion
6.334356
Sum squared resid
605.2873
Schwarz criterion
6.433542
Log likelihood
-67.67792
Hannan-Quinn criter.
6.357721
F-statistic
50.62761
Durbin-Watson stat
1.846406
Prob(F-statistic)
0.000001
由上可知,关系式为y=38.79424+0.331971x2
③关于人均寿命与一岁儿童疫苗接种率的关系,用Eviews分析如下:
Dependent Variable: Y
Method: Least Squares
Date: 11/26/14 Time: 21:14
Sample: 1 22
Included observations: 22
Variable
Coefficient
Std. Error
t-Statistic
Prob.
C
31.79956
6.536434
4.864971
0.0001
X3
0.387276
0.080260
4.825285
0.0001
R-squared
0.537929
Mean dependent var
62.50000
Adjusted R-squared
0.514825
S.D. dependent var
10.08889
S.E. of regression
7.027364
Akaike info criterion
6.824009
Sum squared resid
987.6770
Schwarz criterion
6.923194
Log likelihood
-73.06409
Hannan-Quinn criter.
6.847374
F-statistic
23.28338
Durbin-Watson stat
0.952555
Prob(F-statistic)
0.000103
由上可知,关系式为y=31.79956+0.387276x3
(2)①关于人均寿命与人均GDP模型,由上可知,可决系数为0.526082,说明所建模型整体上对样本数据拟合较好。
对于回归系数的t检验:t(β1)=4.711834>t0.025(20)=2.086,对斜率系数的显著性检验表明,人均GDP对人均寿命有显著影响。
②关于人均寿命与成人识字率模型,由上可知,可决系数为0.716825,说明所建模型整体上对样本数据拟合较好。
对于回归系数的t检验:t(β2)=7.115308>t0.025(20)=2.086,对斜率系数的显著性检验表明,成人识字率对人均寿命有显著影响。
③关于人均寿命与一岁儿童疫苗的模型,由上可知,可决系数为0.537929,说明所建模型整体上对样本数据拟合较好。
对于回归系数的t检验:t(β3)=4.825285>t0.025(20)=2.086,对斜率系数的显著性检验表明,一岁儿童疫苗接种率对人均寿命有显著影响。
2.2
(1)
①对于浙江省预算收入与全省生产总值的模型,用Eviews分析结果如下:
Dependent Variable: Y
Method: Least Squares
Date: 12/03/14 Time: 17:00
Sample (adjusted): 1 33
Included observations: 33 after adjustments
Variable
Coefficient
Std. Error
t-Statistic
Prob.
X
0.176124
0.004072
43.25639
0.0000
C
-154.3063
39.08196
-3.948274
0.0004
R-squared
0.983702
Mean dependent var
902.5148
Adjusted R-squared
0.983177
S.D. dependent var
1351.009
S.E. of regression
175.2325
Akaike info criterion
13.22880
Sum squared resid
951899.7
Schwarz criterion
13.31949
Log likelihood
-216.2751
Hannan-Quinn criter.
13.25931
F-statistic
1871.115
Durbin-Watson stat
0.100021
Prob(F-statistic)
0.000000
②由上可知,模型的参数:斜率系数0.176124,截距为—154.3063
③关于浙江省财政预算收入与全省生产总值的模型,检验模型的显著性:
1)可决系数为0.983702,说明所建模型整体上对样本数据拟合较好。
2)对于回归系数的t检验:t(β2)=43.25639>t0.025(31)=2.0395,对斜率系数的显著性检验表明,全省生产总值对财政预算总收入有显著影响。
④用规范形式写出检验结果如下:
Y=0.176124X—154.3063
(0.004072) (39.08196)
t= (43.25639) (-3.948274)
R2=0.983702 F=1871.115 n=33
⑤经济意义是:全省生产总值每增加1亿元,财政预算总收入增加0.176124亿元。
(2)当x=32000时,
①进行点预测,由上可知Y=0.176124X—154.3063,代入可得:
Y= Y=0.176124*32000—154.3063=5481.6617
②进行区间预测:
先由Eviews分析:
X
Y
Mean
6000.441
902.5148
Median
2689.280
209.3900
Maximum
27722.31
4895.410
Minimum
123.7200
25.87000
Std. Dev.
7608.021
1351.009
Skewness
1.432519
1.663108
Kurtosis
4.010515
4.590432
Jarque-Bera
12.69068
18.69063
Probability
0.001755
0.000087
Sum
198014.5
29782.99
Sum Sq. Dev.
1.85E+09
58407195
Observations
33
33
由上表可知,
∑x2=∑(Xi—X)2=δ2x(n—1)= 7608.0212 x (33—1)=1852223.473
(Xf—X)2=(32000— 6000.441)2=675977068.2
当Xf=32000时,将相关数据代入计算得到:
5481.6617—2.0395x175.2325x√1/33+1852223.473/675977068.2≤
Yf≤5481.6617+2.0395x175.2325x√1/33+1852223.473/675977068.2
即Yf的置信区间为(5481.6617—64.9649, 5481.6617+64.9649)
(3) 对于浙江省预算收入对数与全省生产总值对数的模型,由Eviews分析结果如下:
Dependent Variable: LNY
Method: Least Squares
Date: 12/03/14 Time: 18:00
Sample (adjusted): 1 33
Included observations: 33 after adjustments
Variable
Coefficient
Std. Error
t-Statistic
Prob.
LNX
0.980275
0.034296
28.58268
0.0000
C
-1.918289
0.268213
-7.152121
0.0000
R-squared
0.963442
Mean dependent var
5.573120
Adjusted R-squared
0.962263
S.D. dependent var
1.684189
S.E. of regression
0.327172
Akaike info criterion
0.662028
Sum squared resid
3.318281
Schwarz criterion
0.752726
Log likelihood
-8.923468
Hannan-Quinn criter.
0.692545
F-statistic
816.9699
Durbin-Watson stat
0.096208
Prob(F-statistic)
0.000000
①模型方程为:lnY=0.980275lnX-1.918289
②由上可知,模型的参数:斜率系数为0.980275,截距为-1.918289
③关于浙江省财政预算收入与全省生产总值的模型,检验其显著性:
1)可决系数为0.963442,说明所建模型整体上对样本数据拟合较好。
2)对于回归系数的t检验:t(β2)=28.58268>t0.025(31)=2.0395,对斜率系数的显著性检验表明,全省生产总值对财政预算总收入有显著影响。
④经济意义:全省生产总值每增长1%,财政预算总收入增长0.980275%
2.4
(1)对建筑面积与建造单位成本模型,用Eviews分析结果如下:
Dependent Variable: Y
Method: Least Squares
Date: 12/01/14 Time: 12:40
Sample: 1 12
Included observations: 12
Variable
Coefficient
Std. Error
t-Statistic
Prob.
X
-64.18400
4.809828
-13.34434
0.0000
C
1845.475
19.26446
95.79688
0.0000
R-squared
0.946829
Mean dependent var
1619.333
Adjusted R-squared
0.941512
S.D. dependent var
131.2252
S.E. of regression
31.73600
Akaike info criterion
9.903792
Sum squared resid
10071.74
Schwarz criterion
9.984610
Log likelihood
-57.42275
Hannan-Quinn criter.
9.873871
F-statistic
178.0715
Durbin-Watson stat
1.172407
Prob(F-statistic)
0.000000
由上可得:建筑面积与建造成本的回归方程为:
Y=1845.475--64.18400X
(2)经济意义:建筑面积每增加1万平方米,建筑单位成本每平方米减少64.18400元。
(3)
①首先进行点预测,由Y=1845.475--64.18400X得,当x=4.5,y=1556.647
②再进行区间估计:
用Eviews分析:
Y
X
Mean
1619.333
3.523333
Median
1630.000
3.715000
Maximum
1860.000
6.230000
Minimum
1419.000
0.600000
Std. Dev.
131.2252
1.989419
Skewness
0.003403
-0.060130
Kurtosis
2.346511
1.664917
Jarque-Bera
0.213547
0.898454
Probability
0.898729
0.638121
Sum
19432.00
42.28000
Sum Sq. Dev.
189420.7
43.53567
Observations
12
12
由上表可知,
∑x2=∑(Xi—X)2=δ2x(n—1)= 1.9894192 x (12—1)=43.5357
(Xf—X)2=(4.5— 3.523333)2=0.95387843
当Xf=4.5时,将相关数据代入计算得到:
1556.647—2.228x31.73600x√1/12+43.5357/0.95387843≤
Yf≤1556.647+2.228x31.73600x√1/12+43.5357/0.95387843
即Yf的置信区间为(1556.647—478.1231, 1556.647+478.1231)
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