收藏 分销(赏)

高考数学复习回扣4三角函数与平面向量理市赛课公开课一等奖省名师优质课获奖PPT课件.pptx

上传人:快乐****生活 文档编号:12673915 上传时间:2025-11-22 格式:PPTX 页数:54 大小:7.08MB 下载积分:14 金币
下载 相关 举报
高考数学复习回扣4三角函数与平面向量理市赛课公开课一等奖省名师优质课获奖PPT课件.pptx_第1页
第1页 / 共54页
高考数学复习回扣4三角函数与平面向量理市赛课公开课一等奖省名师优质课获奖PPT课件.pptx_第2页
第2页 / 共54页


点击查看更多>>
资源描述
,回扣,4,三角函数与平面向量,考前回扣,1/54,基础回归,易错提醒,回归训练,2/54,基础回归,3/54,1.,准确记忆六组诱导公式,对于,“,,,k,Z,”,三角函数值与,角三角函数值关系口诀:奇变偶不变,符号看象限,.,2.,三角函数恒等变换,“,四大策略,”,(1),常值代换:尤其是,“,1,”,代换,,1,sin,2,cos,2,tan 45,等,.,(2),降次与升次:正用二倍角公式升次,逆用二倍角公式降次,.,(3),弦、切互化:普通是切化弦,.,4/54,3.,三种三角函数性质,函数,y,sin,x,y,cos,x,y,tan,x,图象,5/54,6/54,7/54,4.,函数,y,A,sin(,x,)(,0,,,A,0),图象,(1),“,五点法,”,作图,(2),由三角函数图象确定解析式时,普通利用五点中零点或最值点作为解题突破口,.,8/54,(3),图象变换,9/54,10/54,11/54,8.,平面向量数量积,(1),若,a,,,b,为非零向量,夹角为,,则,ab,|,a|b,|cos,.,(2),设,a,(,x,1,,,y,1,),,,b,(,x,2,,,y,2,),,则,ab,x,1,x,2,y,1,y,2,.,9.,两个非零向量平行、垂直充要条件,若,a,(,x,1,,,y,1,),,,b,(,x,2,,,y,2,),,则,(1),a,b,a,b,(,b,0,),x,1,y,2,x,2,y,1,0.,(2),a,b,ab,0,x,1,x,2,y,1,y,2,0.,12/54,13/54,12.,三角形,“,四心,”,向量形式充要条件,设,O,为,ABC,所在平面上一点,角,A,,,B,,,C,所正确边长分别为,a,,,b,,,c,,则,14/54,易错提醒,15/54,1.,利用同角三角函数平方关系式求值时,不要忽略角范围,要先判断函数值符号,.,2.,在求三角函数值域,(,或最值,),时,不要忽略,x,取值范围,.,3.,求函数,f,(,x,),A,sin(,x,),单调区间时,要注意,A,与,符号,当,0,时,需把,符号化为正值后求解,.,4.,三角函数图象变换中,注意由,y,sin,x,图象变换得到,y,sin(,x,),时,平移量为,,而不是,.,16/54,5.,在已知两边和其中一边对角时,要注意检验解是否满足,“,大边对大角,”,,防止增解,.,6.,要尤其注意零向量带来问题:,0,模是,0,,方向任意,并不是没有方向;,0,与任意非零向量平行,.,7.,ab,0,是,a,,,b,为锐角必要不充分条件;,ab,0,是,a,,,b,为钝角必要不充分条件,.,17/54,III,回归训练,18/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,19/54,答案,解析,2.,以下函数中,最小正周期为,偶函数是,解析,化简函数解析式,,A,中,,y,cos 2,x,是最小正周期为,偶函数,.,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,20/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,解得,b,1,,故选,A.,21/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,22/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,23/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,24/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,25/54,解析,设,BC,边上高,AD,交,BC,于点,D,,,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,26/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,27/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,sin(,),sin,(,),2,sin(,)cos 2,cos(,)sin 2,28/54,cos(,),cos,(,),2,cos(,)cos 2,sin(,)sin 2,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,29/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,30/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,解析,如图,,31/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,32/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,33/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,34/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,35/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,1,36/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,37/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,38/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,解析,由两个三角函数图象对称中心完全相同可知,两函数周期相同,故,2,,,39/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,13.,在,ABC,中,内角,A,,,B,,,C,对边分别是,a,,,b,,,c,,角,B,为锐角,且,sin,2,B,8sin,A,sin,C,,则,取值范围为,_.,40/54,解析,因为,sin,2,B,8sin,A,sin,C,,由正弦定理可知,,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,41/54,答案,解析,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,42/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,设,ABC,三个内角,A,,,B,,,C,所正确边分别为,a,,,b,,,c,,,43/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,所以,b,2,R,sin,B,,,c,2,R,sin,C,,,44/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,代入上式整理,得,cos,B,cos,C,cos,A,m,sin,C,,,45/54,解答,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,(1),求角,B,大小;,46/54,解答,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,(2),若,a,2,,,b,,求,ABC,面积,.,47/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,48/54,解答,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,49/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,50/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,51/54,解答,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,(2),设,ABC,内角,A,,,B,,,C,所正确边分别为,a,,,b,,,c,,且,c,,,f,(,C,),2,,若向量,m,(1,,,a,),与向量,n,(2,,,b,),共线,求,a,,,b,值,.,52/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,向量,m,(1,,,a,),与向量,n,(2,,,b,),共线,,b,2,a,0,,即,b,2,a,.,53/54,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,即,a,2,b,2,ab,3.,由,得,a,1,,,b,2.,54/54,
展开阅读全文

开通  VIP会员、SVIP会员  优惠大
下载10份以上建议开通VIP会员
下载20份以上建议开通SVIP会员


开通VIP      成为共赢上传

当前位置:首页 > 包罗万象 > 大杂烩

移动网页_全站_页脚广告1

关于我们      便捷服务       自信AI       AI导航        抽奖活动

©2010-2026 宁波自信网络信息技术有限公司  版权所有

客服电话:0574-28810668  投诉电话:18658249818

gongan.png浙公网安备33021202000488号   

icp.png浙ICP备2021020529号-1  |  浙B2-20240490  

关注我们 :微信公众号    抖音    微博    LOFTER 

客服