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Click to edit Master title style,Click to edit Master text styles,Second level,Third level,Fourth level,Fifth level,*,第二部分 章测试,第二章 不等式,(A),一、选择题,:,本大题共,15,小题,每小题,5,分,共,75,分,.,在每小题给出的四个选项中,只有一项是符合题目要求的,.,1,.,已知,ab,cd,那么,(,),A,.a-cb-d,D,.a-c,b-d,2,.,已知,a,b,R,且,abb,是,a,2,b,2,的,(,),A,.,充分非必要条件,B,.,必要非充分条件,C,.,充要条件,D,.,既不充分也不必要条件,4,.,下列命题中正确的是,(,),A,.,若,x,2,x,则,x,0,B,.,若,x,0,则,x,2,x,C,.,若,xx,D,.,若,x,2,x,则,x,0,且,x,1,那么,(,),A,.x+,2B,.x+,可大于也可等于,2,C,.x+,可小于也可等于,2D,.x+,2,6,.,设,0,a,2,ab ba,B,.a,2,ab a,2,+b,2,b,C,.ab,2,aba,2,+b,2,D,.a b,2,ab,1B,.,可大于也可等于,1,C,.,可小于也可等于,1D,.,6,的解是,(,),A,.x,6B,.x,6,C,.x,6D,.-,6,x,6,D,B,9,.,不等式,x,2,+,4,x+,4,0,的解集是,(,),A,.,全体实数,B,.,空集,C,.,x|x=-,2,D,.,x|x,-,2,10,.,不等式,1,的解集是,(,),A,.,x|x,1,C,.,x|x,0,x,R,D,.,x|x,1,11,.,函数,中,自变量,x,的取值范围是,(,),A,.-,2,x,2,且,x,-,1,B,.x,-,2,或,x,2,C,.-,2,x,2,且,x,-,1,D,.x,2,C,D,A,12,.,如果不等式,(,m-,2),x,2,+,2(,m-,2),x-,4,2,C,.-,2,m,2,D,.-,2,m,2,13,.,已知方程,(,k-,1),x,2,-,2,x+,3,=,0,有两个不相等的实数根,则实数,k,的取值范围是,(,),A,.k,C,.k,且,k,1,D,C,14,.,设,则,a,b,c,的大小顺序是,(,),A,.abc,B,.acb,C,.cab,D,.bca,15,.,已知,a,b,R,且,a+b=,3,则,2,a,+,2,b,的最小值为,(,),A,.,6B,.,4C,.,2D,.,B,B,二、填空题,:,本大题共,5,小题,每小题,5,分,共,25,分,.,16,.,不等式,|,1,-,2,x|,5,的解集是,.,17,.,不等式,的解集是,.,18,.,函数,中,自变量,x,的取值范围是,.,19,.,已知,x,y,R,那么,x,2,+,4,y,2,-,6,x+,8,y,的最小值是,.,20,.,不等式,9,x,+,23,x+,1,-,16,0,的解是,.,三、解答题,:,本大题共有,4,小题,共,50,分,.,解答应写出文字说明、证明过程或推演步骤,.,21,.,若,x-,1,则,x,为何值时,有最小值,最小值为多少,?,22,.,设,a,0,解关于,x,的不等式,23,.,某工厂要建造一个长方体无盖贮水池,其容积为,4800m,3,深为,3m,如果池底每,1m,2,的造价为,150,元,池壁每,1m,2,的造价为,120,元,问怎样设计水池能使总造价最低,最低总造价是多少元,?,24,.,已知,x+y=,1,求,x,2,+y,2,的最小值,.,
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