1、一、 Spreader bar selection (refer to drawing T3510-Lifting Sketch-3) a、平衡梁选择(参见图T3510-吊装草图-3) The spreader bar uses the steel pipe ofφ219×8, material=20#, length=3.8m, mechanics specialty is F=5300mm2,rotating radius isr=74.48 mm 平衡梁选用φ219×8的钢管,材质20#,长3.8米,其力学特性为截面积F=5300mm2,回转半径r=74.48 mm Sprea
2、der bar pulling is P2= P1cos19.5=Q/2 =120.68/2t P2=64.19t=629062N P2----------吊装梁所受正压力 平衡梁受力为 P2= P1cos19.5=Q/2 =120.68/2t P2=64.19t=629062N Spreader bar slightness ratio: λ=μl/r=3800
3、/74.48=51.02 平衡梁细长比: λ=μl/r=3800/74.48=51.02 From above u-----length factor. Two ends hinge u=1 L----Supporting girder length L=3.8m 上式中u-----长度系数、两端铰支 u=1 L-----支撑梁长 L=3.8m 折减系数 Φ=1.018-0.0023*51.02=0
4、9 Reduction coefficient Φ=1.018-0.0023*51.02=0.9 Spreader bar stress[σ]= P2/(ΦF)= 629062/ (0.9×5300)=131N/mm2 平衡梁应力为[σ]= P2/(ΦF)= 629062/(0.9×5300)=131N/mm2 Bend limit of steel tube isσs=245.15N/mm2 Take safety factor n=1.8 钢管的屈服极限为:σs=245.15N/mm2取安全系数n=1.8 [δ] = δs /n =245.15/1.8 = 136.1
5、9N/mm2>σ b、两端夹板钢板计算 钢板所受应力 δ=P2/A =629062N/102050 mm2 =6.16N/ mm2 δ-----钢板所受压应力N/ mm2 P2----吊装梁所受正压力N A------受压面积mm2 钢板δ=20 Q235 的屈服极限为:σs=225N/mm2取安全系数n=1.8 [δ] = δs /n =225/1.8 = 125N/mm2>δ,钢板满足要求. C、对夹螺栓的计算 F1=G/2+f=G/2sin70 F1-----钢丝绳受力64.19T=629062N f--------钢丝绳受摩擦力f=F2*ζ+n*
6、N*ζ*2 N--------螺栓对钢丝绳的压力(t) ζ-------钢丝绳在钢板上摩擦系数ζ=0.2 n--------螺栓数量选4套 G/2sin70-G/2=G/2ctg70*0.2+4*N*0.2*2 N=2.3T 选用M20的螺栓,4套;查表得M20的螺栓旋紧螺母时螺栓对钢板的压力大小为2.5T。满足使用要求。此时螺栓的扭矩值为60N.M 二、 Spreader bar selection (refer to drawing T3510-Lifting Sketch-3) a、平衡梁选择(参见图T3310-吊装草图-3) The spreader bar uses
7、 the steel pipe ofφ219×8, material=20#, length=3.8m, mechanics specialty is F=5300mm2,rotating radius isr=74.48 mm 平衡梁选用φ219×8的钢管,材质20#,长2.7米,其力学特性为截面积F=5300mm2,回转半径r=74.48 mm Spreader bar pulling is P2= P1cos30=Q/2 =80.1/2t P2=46.03t=451094
8、N P2----------吊装梁所受正压力 平衡梁受力为 P2= P1cos30=Q/2 =80.1/2t P2=46.03t=451094N Spreader bar slightness ratio: λ=μl/r=2700/74.48=36.25 平衡梁细长比: λ=μl/r=2700/74.48=36.25 From above u-----length factor. Two ends hinge u=1 L----S
9、upporting girder length L=2.7m 上式中u-----长度系数、两端铰支 u=1 L-----支撑梁长 L=3.8m 折减系数 Φ=1.018-0.0023*36.25=0.93 Reduction coefficient Φ=1.018-0.0023*36.25=0.93 Spreader bar stress[σ]= P2/(ΦF)= 451094/ (0.93×5300)=91.51N/mm2 平衡梁应
10、力为[σ]= P2/(ΦF)= 451094/ (0.93×5300)=91.51N/mm2 Bend limit of steel tube isσs=245.15N/mm2 Take safety factor n=1.8 钢管的屈服极限为:σs=245.15N/mm2取安全系数n=1.8 [δ] = δs /n =245.15/1.8 = 136.19N/mm2>σ b、两端夹板钢板计算 钢板所受应力 δ=P2/A =451094N/102050 mm2 =4.42N/ mm2 δ-----钢板所受压应力N/ mm2 P2----吊装梁所受正压力N A--
11、受压面积mm2 钢板δ=20 Q235 的屈服极限为:σs=225N/mm2取安全系数n=1.8 [δ] = δs /n =225/1.8 = 125N/mm2>δ,钢板满足要求. C、对夹螺栓的计算 F1=G/2+f=G/2sin70 F1-----钢丝绳受力46.03t =451094N f--------钢丝绳受摩擦力f=F2*ζ+n*N*ζ*2 N--------螺栓对钢丝绳的压力(t) ζ-------钢丝绳在钢板上摩擦系数ζ=0.2 n--------螺栓数量选4套 G/2sin60-G/2=G/2ctg60*0.2+4*N*0.2*2 N=1.2T 选用M20的螺栓,4套;查表得M20的螺栓旋紧螺母时螺栓对钢板的压力大小为2.5T。满足使用要求。此时螺栓的扭矩值为30N.M






