ImageVerifierCode 换一换
格式:DOCX , 页数:19 ,大小:25.85KB ,
资源ID:4540911      下载积分:5 金币
验证码下载
登录下载
邮箱/手机:
验证码: 获取验证码
温馨提示:
支付成功后,系统会自动生成账号(用户名为邮箱或者手机号,密码是验证码),方便下次登录下载和查询订单;
特别说明:
请自助下载,系统不会自动发送文件的哦; 如果您已付费,想二次下载,请登录后访问:我的下载记录
支付方式: 支付宝    微信支付   
验证码:   换一换

开通VIP
 

温馨提示:由于个人手机设置不同,如果发现不能下载,请复制以下地址【https://www.zixin.com.cn/docdown/4540911.html】到电脑端继续下载(重复下载【60天内】不扣币)。

已注册用户请登录:
账号:
密码:
验证码:   换一换
  忘记密码?
三方登录: 微信登录   QQ登录  
声明  |  会员权益     获赠5币     写作写作

1、填表:    下载求助     索取发票    退款申请
2、咨信平台为文档C2C交易模式,即用户上传的文档直接被用户下载,收益归上传人(含作者)所有;本站仅是提供信息存储空间和展示预览,仅对用户上传内容的表现方式做保护处理,对上载内容不做任何修改或编辑。所展示的作品文档包括内容和图片全部来源于网络用户和作者上传投稿,我们不确定上传用户享有完全著作权,根据《信息网络传播权保护条例》,如果侵犯了您的版权、权益或隐私,请联系我们,核实后会尽快下架及时删除,并可随时和客服了解处理情况,尊重保护知识产权我们共同努力。
3、文档的总页数、文档格式和文档大小以系统显示为准(内容中显示的页数不一定正确),网站客服只以系统显示的页数、文件格式、文档大小作为仲裁依据,平台无法对文档的真实性、完整性、权威性、准确性、专业性及其观点立场做任何保证或承诺,下载前须认真查看,确认无误后再购买,务必慎重购买;若有违法违纪将进行移交司法处理,若涉侵权平台将进行基本处罚并下架。
4、本站所有内容均由用户上传,付费前请自行鉴别,如您付费,意味着您已接受本站规则且自行承担风险,本站不进行额外附加服务,虚拟产品一经售出概不退款(未进行购买下载可退充值款),文档一经付费(服务费)、不意味着购买了该文档的版权,仅供个人/单位学习、研究之用,不得用于商业用途,未经授权,严禁复制、发行、汇编、翻译或者网络传播等,侵权必究。
5、如你看到网页展示的文档有www.zixin.com.cn水印,是因预览和防盗链等技术需要对页面进行转换压缩成图而已,我们并不对上传的文档进行任何编辑或修改,文档下载后都不会有水印标识(原文档上传前个别存留的除外),下载后原文更清晰;试题试卷类文档,如果标题没有明确说明有答案则都视为没有答案,请知晓;PPT和DOC文档可被视为“模板”,允许上传人保留章节、目录结构的情况下删减部份的内容;PDF文档不管是原文档转换或图片扫描而得,本站不作要求视为允许,下载前自行私信或留言给上传者【二***】。
6、本文档所展示的图片、画像、字体、音乐的版权可能需版权方额外授权,请谨慎使用;网站提供的党政主题相关内容(国旗、国徽、党徽--等)目的在于配合国家政策宣传,仅限个人学习分享使用,禁止用于任何广告和商用目的。
7、本文档遇到问题,请及时私信或留言给本站上传会员【二***】,需本站解决可联系【 微信客服】、【 QQ客服】,若有其他问题请点击或扫码反馈【 服务填表】;文档侵犯商业秘密、侵犯著作权、侵犯人身权等,请点击“【 版权申诉】”(推荐),意见反馈和侵权处理邮箱:1219186828@qq.com;也可以拔打客服电话:4008-655-100;投诉/维权电话:4009-655-100。

注意事项

本文(C语言编写的推箱子游戏.docx)为本站上传会员【二***】主动上传,咨信网仅是提供信息存储空间和展示预览,仅对用户上传内容的表现方式做保护处理,对上载内容不做任何修改或编辑。 若此文所含内容侵犯了您的版权或隐私,请立即通知咨信网(发送邮件至1219186828@qq.com、拔打电话4008-655-100或【 微信客服】、【 QQ客服】),核实后会尽快下架及时删除,并可随时和客服了解处理情况,尊重保护知识产权我们共同努力。
温馨提示:如果因为网速或其他原因下载失败请重新下载,重复下载【60天内】不扣币。 服务填表

C语言编写的推箱子游戏.docx

1、/* 一个C语言编写的推箱子游戏源代码7/*本游戏是字符模式的,请不要在中文dos下运行。本游戏在TURBO C下调试通过*/include include include include include include /*定义二维数组ghouse来记录屏幕上各点的状态,其中:。表示什么都没有,b表示箱子,w、表示墙壁,m,表示目的地,T表示箱子 在目的地。*/char ghouse2020;/*以下函数为直接写屏函数,很酷的函数哦!是我朋友告诉我的。*/char far *screen=(char far* )0xb8000000;void putchxy(int y,int x,char

2、 ch.char fc,char be)screen(x*160)+(y1 )+0=ch;screen(x*160)+(y1 )+1 =(bc*16)+fc;)/*定义判断是否胜利的数据结构7typedef struct winer int x.y;struct winer *p;Jwiner;/*箱子位置的数据结构*/typedef struct boxs int x,y;struct boxs *next;boxs;/*在特定的坐标上画墙壁并用数组记录状态的函数7default: break;)/*判断特定的坐标上的状态*/int judge(int x,int y)(inti;switc

3、h(ghousexy)(case 0: i=1;break;case w: i=0;break;case b: i=2;break;case T: i=4;break;casem: i=3;break;default: break;)return i;)/*处理按下键盘后,人物移动的主函数*/move(int x.int y,char a)(switch(a)(case u:if(!judge(x-1 ,y) gotoxy(y,x);break; else ifQudge(x-1 ,y)=1|judge(x-1 ,y)=3) if(judge(x,y)=3)printwhither(x,y);

4、printman(x-1 ,y);break;elseprintf( );printman(x-1 ,y);break;)else ifQudge(x-1,y)=2)if(judge(x-2,y)=1)movebox(xsy;u);ifQudge(x,y)=3) printwhither(x,y); gotoxy(y,x-1);)else if(judge(x-2,y)=3) moveboxin(x,y;u,);ifQudge(x,y)=3) printwhither(x,y); gotoxy(y,x-1);)else gotoxy(y,x);break;)else if(judge(x-1,

5、y)=4)if(judge(x-2,y)=1)moveinbox(x,y,u);if(judge(x,y)=3) printwhither(x,y);gotoxy(y,x-1);)else if(judge(x-2,y)=3) moveinboxinfx.y/u*);if(judge(x,y)=3) printwhither(x,y);gotoxy(y,x-1);)else gotoxy(y,x);break;)case d:if(!judge(x+1 ,y) gotoxy(y,x);break;else if(judge(x+1 ,y)=1 |judge(x+1 ,y)=3)if(judge

6、(x,y)=3)printwhither(xsy);printman(x+1 ,y);break; elseprintf(H M);printman(x+1 ,y);break;)else if(judge(x+1,y)=2) if(judge(x+2,y)=1)movebox(x,y;d);ifQudge(x,y)=3) printwhither(x,y);gotoxy(y,x+1);)else if(judge(x+2,y)=3)moveboxin(x,y,d);ifQudge(x,y)=3) printwhither(x,y);gotoxy(y,x+1);)else gotoxy(y,x

7、);break;)else if(judge(x+1,y)=4)if(judge(x+2,y)=1)moveinbox(x,y;d);if(judge(x,y)=3) printwhither(x,y);gotoxy(y,x+1);)else if(judge(x+2,y)=3)moveinboxin(x,y;d);ifQudge(x,y)=3) printwhither(x,y);gotoxy(y,x+1);)else gotoxy(y,x);break;)case T:if(!judge(x,y-1) gotoxy(y,x);break;else ifQudge(x,y-1)=1 |jud

8、ge(x,y-1)=3)if(judge(x,y)=3)printwhither(x,y);printman(x,y-1);break; elseprintf( );printman(x,y-1 );break;)else if(judge(x,y-1)=2)if(judge(x,y-2)=1)movebox(x,y,T);if(judge(x,y)=3) printwhither(x,y); gotoxy(y-1,x);)else if(judge(x,y-2)=3)moveboxin(x,y,T);if(judge(x,y)=3) printwhither(x,y); gotoxy(y-1

9、 ,x);)else gotoxy(y,x);break;)else if(judge(x,y-1)=4)if(judge(x,y-2)=1)moveinbox(x,y,T);if(judge(x,y)=3) printwhither(x,y); gotoxy(y-1,x);)else if(judge(x,y-2)=3)moveinboxin(x,y,T);if(judge(x,y)=3) printwhither(x,y); gotoxy(y-1 ,x);)else gotoxy(y,x);break;)case r:if(!judge(x,y+1) gotoxy(y,x);break;e

10、lse ifQudge(x,y+1 )=1 |judge(x,y+1)=3)if(judge(x,y)=3)printwhither(x,y);printman(x,y+1);break; elseprintf( );printman(x,y+1 );break;)else if(judge(x,y+1)=2)if(judge(x,y+2)=1)movebox(x,y;r);if(judge(x,y)=3) printwhither(x,y); gotoxy(y+1,x);)else if(judge(x,y+2)=3)moveboxin(x,y,r);ifQudge(x,y)=3) prin

11、twhither(x,y); gotoxy(y+1 ,x);)else gotoxy(y,x);break;)else if(judge(x,y+1)=4)if(judge(x,y+2)=1)moveinbox(x5y,r,);ifQudge(x,y)=3) printwhither(x,y); gotoxy(y+1,x);)else if(judge(x,y+2)=3)moveinboxin(x,y,r);if(judge(x,y)=3) printwhither(x,y); gotoxy(y+1 ,x);)else gotoxy(y,x); break;) default: break;)

12、r按下空格键后因到本关开头的函数*/ void reset(int i)(switch(i)(case 0: init();inithouse1();break;case 1: init();inithouse2();break;init();inithouse3();break;case 2: init();inithouse4();break;default:break;)/*主函数main*/void main()(int key,x,y,s,i=0;winer *win,*pw;_AL=3;_AH=0;geninterrupt(OxW);init();win=inithouse1();

13、doAH=3;geninterrupt(OxlO);x=_DH+1 ;y=_DL+1;while(bioskey(1)=0);key=bioskey(0);switch(key)(case 0x4800:move(x,y;u);break; /* 按下向上键后 7case 0x5000:move(x,y;d);break; /* 按下向下健后 7case 0x4b00:move(x,y,T);break; /* 按下向左键后 7case 0x4d00:move(x,y,r);break; /* 按下向右键后 7case 0x3920:reset(i);break; /* 按下空格键后 */ d

14、efault:break;)s=0;pw=win;while(pw)(if(ghousepw-xpw-y=m) s+;pw=pw-p;)if(s=O)(free(win);gotoxy(25,2);printf(congratulate! you did a good job!);getch();i+; switch(i) (case 1: init();win=inithouse2();break;case 2: init();win=inithouse3();break;case 3: init();win=inithouse4();break;case 4: gotoxy(15,21);

15、printf(My dear Friend, How smart you are! Welcome to play again!); key=0x011b;getch();break;default: break;)while(key!=OxO11b);AL=3;_AH=O;geninterrupt(OxlO);)附录资料:不需要的可以自行删除Abstract: Based on the comprehensive analysis on the plastic parts structure service requirement, mounding quality and mould me

16、nu factoring cost. A corresponding injection mould of internal side core pulling was designed. By adopting the multi-direction and multi-combination core-pulling. A corresponding injection mould of internal side core pulling was designed, the working process of the mould was introducedC语言详解一枚举类型注:以下

17、全部代码的执行环境为VC+ 6.0在程序中,可能需要为某些整数定义个别名,我们可以利用预处理指令#dcfine来完成这 项工作,您的代码可能是:#define MON 1#defineTUE 2#define WED 3#defineTHU 4# define FRI 5dcfine SAT 6# define SUN 7在此,我们定义一种新的数据类型,希望它能完成同样的工作。这种新的数据类型叫枚举型。1 .定义一种新的数据类型-枚举型以下代码定义了这种新的数据类型-枚举型enum DAYMON=1,TUE, WED, THU, FRI, SAT, SUN(i)枚举型是一个集合,集合中的元素(

18、枚举成员)是一些命名的整型常量,元素之间用逗号, 隔开。(2) DAY是一个标识符,可以看成这个集合的名字,是一个可选项,即是可有可无的项。(3)第一个枚举成员的默认值为整型的0,后续枚举成员的值在前一个成员上加1。(4)可以人为设定枚举成员的值,从而自定义某个范围内的整数。(5)枚举型是预处理指令#dMne的替代。(6)类型定义以分号;结束。2 .使用枚举类型对变吊进行声明新的数据类型定义完成后,它就可以使用了。我们已经见过最基本的数据类型,如:整型int, 单精度浮点型float,双精度浮点型double,字符型char,短整型short等等。用这些基本数据 类型声明变量通常是这样:cha

19、ra; 变量a的类型均为字符型charcharletter;int x,y,z; 变量x,y和z的类型均为整型intint number;double m, n;double result; 变量result的类型为双精度浮点型double既然枚举也是一种数据类型,那么它和基本数据类型一样也可以对变量进行声明。方法一:枚举类型的定义和变量的声明分开enuni DAY|MON=1,TUE, WED. THU, FRI, SAT, SUN;enum DAY yesterday;enum DAY today;enum DAY tomorrow; 变量 tomorrow 的类型为枚举型 enum DA

20、Yenum DAY good_day, bad_day; /变量 good_day 和 bad_day 的类型均为枚举型 enuni DAY方法二:类型定义与变量声明同时进行:enum/跟第一个定义不同的是,此处的标号DAY省略,这是允许的。Saturday,sunday = 0, monday, tuesday, Wednesday, thursday, friday workday; /变量workday的类型为枚举型cnum DAYenum week Mon=l, Tue, Wed, Thu, Fri Sal, Sun days; 变量 days 的类型为枚举型 enum weekenu

21、m BOOLEAN false, (rue end_flag, maich_flag; 定义枚举类型并声明了两个枚举型变 量方法三:用typedef关键字将枚举类型定义成别名,并利用该别名进行变量声明:typedcf enum workday Saturday, sunday = 0, monday, tuesday, Wednesday, thursday, friday workday; 此处的workday为枚举型enum workday的别名workday loday, tomorrow; 变量 uxlay 和 tomorrow 的类型为枚举型 workday,也即 enum work

22、dayenum workday 中的 workday 可以省略:typedef enum (Saturday, sunday = 0, monday, tuesday, Wednesday, thursday, friday workday; /此处的workday为枚举型enum workday的别名workday today, tomorrow; 变量 today 和 tomorrow 的类型为枚举型 workday,也即 enum workday也可以用这种方式:(ypedef enum workdaySaturday, sunday = 0, monday, tuesday, Wedn

23、esday, thursday, friday);workday today, tomorrow; 变量 today 和 tomorrow 的类型为枚举型 workday,也即 enum workday注意:同一个程序中不能定义同名的枚举类型,不同的枚举类型中也不能存在同名的命名常 量。错误例如如下所示: 错误声明一:存在同名的枚举类型typedef enum Wednesday, thursday, friday workday;typedef enum WEEK Saturday, sunday = 0, monday, workday;错误声明二:存在同名的枚举成员typedef enu

24、m Wednesday, thursday, friday workday;typedef enum WEEK Wednesday, sunday = 0,void printwall(int x,int y) putchxy(y-1 ,x-1,219,GREEN,BLACK);ghousexy=w,;)/*在特定的坐标上画箱子并用数组记录状态的函数7void printbox(int x,int y)(putchxy(y-1 ,x-1,10, WHITE,BLACK);ghousexy=b,;)/*在特定的坐标上画目的地并用数组记录状态的函数*/void printwhither1(int

25、x,int y,winer *win,winer *pw)(winer *qw;putchxy(y-1 ,x-1 1YELLOW,BLACK);ghousexy=m;if(*win=NULL)(*win=*pw=qw=(winer* )malloc(sizeof(winer);(*pw)-x=x;(*pw)-y=y;(*pw)-p=NULL; else(qw=(winer* )malloc(sizeof(winer);qw-x=x;qw-y=y;(*pw)-p=qw;(*pw)=qw;qw-p=NULL; )/*在特定的坐标上画目的地并用数组记录状态的函数*/void printwhither

26、(int x,int y)(putchxy(y-1 ,x-1 ;*1,YELLOW,BLACK);ghousexy=m;monday, vvorkday_2;.使用枚举类型的变量2.1 对枚举型的变量赋值。实例将枚举类型的赋值与基本数据类型的赋值进行了比照:方法一:先声明变量,再对变量赋值#include/*定义枚举类型*/enum DAY MON= I, TUE, WED, THU, FRI, SAT, SUN );void main()/*使用基本数据类型声明变量,然后对变量赋值*/int x, y, z;x = 10;y = 20; z = 30;/*使用枚举类型声明变最,再对枚举型变量

27、赋值*/enum DAY yesterday, today, tomorrow;yesterday = MON;today = TUE;tomorrow = WED;printf(%d %d %d n, yesterday, today, tomorrow);1方法二:声明变量的同时赋初值#include /*定义枚举类型*/enum DAY MON=1,TUE, WED, THU, FRI, SAT, SUN ;void main()/*使用基本数据类型声明变量同时对变量赋初值*/int x= 10, y=20, z=30;/*使用枚举类型声明变量同时对枚举型变量赋初值*/enum DAY

28、yesterday = MON,today = TUE, tomorrow = WED;printf(%d %d %d n, yesterday, today, tomorrow);方法三:定义类型的同时声明变量,然后对变量赋值。#include /*定义枚举类型,同时声明该类型的三个变量,它们都为全局变晟*/enum DAY MON=I,TUE, WED, THU, FRI, SAT, SUN yesterday, today, tomorrow;/*定义三个具有基本数据类型的变量,它们都为全局变量*/int x, y, z;void main()(/*对基本数据类型的变量赋值*/x= 10

29、; y = 20; z = 30;/*对枚举型的变量赋值*/yesterday = MON;today = TUE;tomorrow = WED;printf(%d %d %d n, x, y, z); 输出:10 20 30printf(%d %d %d n, yesterday, today, tomorrow); 输出:12 31方法四:类型定义,变显声明,赋初值同时进行。#include /*定义枚举类型,同时声明该类型的三个变量,并赋初值。它们都为全局变量*/enum DAYMON=hTUE,WED,THU,FRI,SAT, SUNyesterday = MON, today = T

30、UE, tomorrow = WED;/*定义三个具有基本数据类型的变量,并赋初值。它们都为全局变量*/int x = 10, y = 20, z = 30;void niain()printf(%d %d %d n, x, y, z); 输出:10 20 30printf(%d %d %d n, yesterday, today, tomorrow); 输出:1 2 313.2 对枚举型的变量赋整数值时,需要进行类型转换。#include enum DAY MON=1, TUE, WED, THU, FRI, SAT. SUN ;void main()(enum DAY yesterday,

31、 today, tomorrow;yesterday = TUE;today = (enum DAY) (yesterday + 1); 类型转换tomorrow = (enum DAY) 30; 类型转换/tomorrow = 3; /错误printf(%d %d %d n, yesterday, today, tomorrow); 输出:2 3 303.3 使用枚举型变量#includcenum(BELL= a;BACKSPACE = b,HTAB= M,RETURN= *rNEWLINE = n,VTAB=W,SPACE=enuni BOOLEAN FALSE = 0. TRUE mat

32、ch_flag;void main()int index = 0;int count_oflletter = 0;int count_oflspace = 0;char strU = Im Ely efod;match_flag = FALSE;for(; strindex != 0; index+) if( SPACE != strindex) count_oUetter+;else(match_flag = (enuni BOOLEAN) 1; count_oLspace+;printf(%s %d times %c, match_flag ? match : not match, cou

33、nt_of_space, NEWLINE); printf(count of letters: %d %c%c, count_oLlcttcr, NEWLINE, RETURN);1输出:match 2 timescount of letters: 10Press any key to continue.枚举类型与sizeof运算符#includc enuniescapes(BELL= a,BACKSPACE = b,HTAB= t;RETURN = r;NEWLINE =n,VTAB= W,SPACE=,enuni BOOLEAN FALSE = 0. TRUE match_flag;voi

34、d main()printf(%d bytes n sizeof(enum escapes); /4 bytesprintf(%d bytes n, sizeof(escapcs); /4 bytesprintf(%d bytes n, sizeof(enum BOOLEAN); /4 bytesprintf(%d bytes n* sizeof(BOOLEAN); /4 bytesprintf(%d bytes n, sizeof(match_flag); /4 bytesprin(f(%d bytes n, sizeof(SPACE); /4 bytesprintf(%d bytes n,

35、 sizeof(NEWLINE); /4 bytesprintf(%d bytes n, sizeof(FALSE); /4 bytesprintf(%d bytes n, sizeof(0); /4 bytes)4 .综合举例#includeenum Seasonspring, summcr=100, fall=96, winter1;(ypedef enumMonday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday Weekday;void main()/* Season */printf(%d n, spring); /

36、0printf(%d, %c n”, summer, summer); / 100, dprinif(d n fall+winter); / 193Season mySeason=wintcr;if(winter=my Season)printf(mySeason is winter n); / mySeason is winterint x=100;if(x=summer)printf(x is equal to summern); / x is equal to summerprintf(%d by(esn sizeof(spring); / 4 bytes/* Weekday */pri

37、ntf(sizcof Weekday is: %d n, sizeof(Weekday); /sizeof Weekday is: 4Weekday today = Saturday;Weekday tomorrow;if(today = Monday)tomorrow = Tuesday;elsetomorrow = (Weekday) (today + 1); /remember to convert from int to Weekday本文来自CSDN-xiaobai32966博客)/*在特定的坐标上画人的函数7void printman(int x,int y)(gotoxy(y,x

38、);AL=02; CX=01; AH=0xa;geninterrupt(OxlO);)/*在特定的坐标上画箱子在目的地上并用数组记录状态的函数*/void printboxin(int x,int y)(putchxy(y-1 ,x-1,10,YELLOW,BLACK);ghousexy=i;)/*初始化函数,初始化数组和屏幕7void init()(int i,j;for(i=0;i20;i+)for(j=0;j20;j+)ghouseij=0;AL=3;AH=0;geninterrupt(OxlO);gotoxy(40,4);printf(Welcome to come box world

39、!*);gotoxy(40,6);printf(Press up,down,left,right to play.);gotoxy(40,8);printf(Press Esc to quit it.);gotoxy(40,10);printf(Press space to reset the game.);gotoxy(40,12);printf(Producer: wangdehao.);gotoxy(40,14);printf(Mar. 30th 2003.);/*第一关的图象初始化7winer *inithouse1()(int x,y;winer *win=NULL,*pw;for(

40、x=1 ,y=5;y=9;y+) printwall(x+4,y+10);for(y=5,x=2;x=5;x+) printwall(x+4,y+10);for(y=9,x=2;x=5;x+) printwall(x+4,y+10);for(y=1 ,x=3;x=8;x+) printwall(x+4,y+10);for(x=3,y=3;x=5;x+)printwall(x+4,y+10);for(x=5,y=8;x=9;x+)printwall(x+4,y+10);for(x=7,y=4;x=9;x+)printwall(x+4,y+10);for(x=9,y=5;y=7;y+)printw

41、all(x+4,y+10);for(x=8,y=2;y=3;y+)printwall(x+4,y+10);printwall(5+4,4+10);printwall(5+4,7+10);printwall(3+4,2+10);printbox(3+4,6+10);printbox(3+4,7+10);printbox(4+4,7+10);printwhitherl (4+4,2+10,&win,&pw);printwhitherl (5+4,2+10,&win,&pw);printwhitherl (6+4,2+10,&win,&pw);printman(2+4,8+10);return wi

42、n;/*第三关的图象初始化7winer *inithouse3()int x,y;winer *win=NULL,*pw;for(x=1 ,y=2;y=8;y+)printwall(x+4,y+10);for(x=2,y=2;x=4;x+)printwall(x+4,y+10);for(x=4,y=1 ;y=3;y+) printwall(x+4,y+10);for(x=5,y=1 ;x=8;x+)printwall(x+4,y+10);for(x=8,y=2;y=5;y+)printwall(x+4,y+10);for(x=5,y=5;x=7;x+)printwall(x+4,y+10);f

43、or(x=7,y=6;y=9;y+)printwall(x+4,y+10);for(x=3,y=9;x=6;x+)printwall(x+4,y+10);for(x=3,y=6;y=8;y+)printwall(x+4,y+10);printwall(2+4,8+10);printwall(5+4,7+10);printbox(6+4,3+10);printbox(4+4,4+10);printbox(5+4,6+10);printwhitherl (2+4,5+10,&win,&pw);printwhitherl (2+4,6+10,&win,&pw);printwhitherl (2+4,

44、7+10,&win,&pw);printman(2+4,4+10);return win;)r第二关的图象初始化7winer *inithouse2()int x,y;winer *win=NULL,*pw;for(x=1 ,y=4;y=7;y+)printwall(x+4,y+10);for(x=2,y=2;y=4;y+)printwall(x+4,y+10);for(x=2,y=7;x=4;x+)printwall(x+4,y+10);for(x=4,y=1 ;x=8;x+)printwall(x+4,y+10);for(x=8,y=2;y=8;y+)printwall(x+4,y+10);for(x=4,y=8;x=8;x+)printwall(x+4,y+10);for(x=4,y=6;x=5;x+)printwall(x+4,y+10);for(x=3,y=2;x=4;x+)printwall(x+4,y+10);for(x=4,y=4;x=5;x+)printwall(x+4,y+10);printwall(6+4,3+10);printbox(3+4,5+10);printbo

移动网页_全站_页脚广告1

关于我们      便捷服务       自信AI       AI导航        获赠5币

©2010-2024 宁波自信网络信息技术有限公司  版权所有

客服电话:4008-655-100  投诉/维权电话:4009-655-100

gongan.png浙公网安备33021202000488号   

icp.png浙ICP备2021020529号-1  |  浙B2-20240490  

关注我们 :gzh.png    weibo.png    LOFTER.png 

客服