《c++程序设计》谭浩强课后习题答案及解析.doc

专业整理
第一章
1.5题
#include
using namespace std;
int main()
{
cout<<"This"<<"is";
cout<<"a"<<"C++";
cout<<"program.";
return 0;
1.6题
#include
using namespace std;
int main()
{
int a,b,c;
a=10;
b=23;
c=a+b;
cout<<"a+b=";
cout<
using namespace std;
int main()
{
int a,b,c;
int f(int x,int y,int z);
cin>>a>>b>>c;
c=f(a,b,c);
cout<z
using namespace std;
int main()
{
int a,b,c;
cin>>a>>b;
c=a+b;
cout<<"a+b="<
using namespace std;
int main()
{
int a,b,c;
int add(int x,int y);
cin>>a>>b;
c=add(a,b);
cout<<"a+b="<
using namespace std;
int main()
{char c1='a',c2='b',c3='c',c4='\101',c5='\116';
cout<
2.4题
#include
using namespace std;
int main()
{char c1='C',c2='+',c3='+';
cout<<"I say: \""<
using namespace std;
int main()
{int i,j,m,n;
i=8;
j10;
m=++i+j++;
n=(++i)+(++j)+m;
cout<
using namespace std;
int main()
{char c1='C', c2='h', c3='i', c4='n', c5='a';
c1+=4;
c2+=4;
c3+=4;
c4+=4;
c5+=4;
cout<<"password is:"< return 0;
}
3.2题
#include
#include
using namespace std;
int main ( )
{float h,r,l,s,sq,vq,vz;
const float pi=3.1415926;
cout<<"please enter r,h:";
cin>>r>>h;
l=2*pi*r;
s=r*r*pi;
sq=4*pi*r*r;
vq=3.0/4.0*pi*r*r*r;
vz=pi*r*r*h;
cout<)<>f;
c=(5.0/9.0)*(f-32); //注意5和9要用实型表示,否则5/9值为0
cout<<"摄氏温度为:"<
using namespace std;
int main ( )
{char c1,c2;
cout<<"请输入两个字符c1,c2:";
c1=getchar(); //将输入的第一个字符赋给c1
c2=getchar(); //将输入的第二个字符赋给c2
cout<<"用putchar函数输出结果为:";
putchar(c1);
putchar(c2);
cout<
using namespace std;
int main ( )
{char c1,c2;
cout<<"请输入两个字符c1,c2:";
c1=getchar(); //将输入的第一个字符赋给c1
c2=getchar(); //将输入的第二个字符赋给c2
cout<<"用putchar函数输出结果为:";
putchar(c1);
putchar(44);
putchar(c2);
cout<
using namespace std;
int main ( )
{char c1,c2;
int i1,i2; //定义为整型
cout<<"请输入两个整数i1,i2:";
cin>>i1>>i2;
c1=i1;
c2=i2;
cout<<"按字符输出结果为:"<
using namespace std;
int main ( )
{ int a=3,b=4,c=5,x,y;
cout<<(a+b>c && b==c)<b) && !c||1)<
using namespace std;
int main ( )
{int a,b,c;
cout<<"please enter three integer numbers:";
cin>>a>>b>>c;
if(a cin>>a>>b>>c;
temp=(a>b)?a:b; /* 将a和b中的大者存入temp中 */
max=(temp>c)?temp:c; /* 将a和b中的大者与c比较，最大者存入max
*/
cout<<"max="<
using namespace std;
int main ( )
{int x,y;
cout<<"enter x:";
cin>>x;
if (x<1)
{y=x;
cout<<"x="< cout<<"x="<
using namespace std;
int main ()
{float score;
char grade;
cout<<"please enter score of student:";
cin>>score;
while (score>100||score<0)
{cout<<"data error,enter data again.";
cin>>score;
}
switch(int(score/10))
{case 10:
case 9: grade='A';break;
case 8: grade='B';break;
case 7: grade='C';break;
case 6: grade='D';break;
default:grade='E';
}
cout<<"score is "<"<
using namespace std;
int main ()
{long int num;
int indiv,ten,hundred,thousand,ten_thousand,place;
/*分别代表个位,十位,百位,千位,万位和位数
*/
cout<<"enter an integer(0~99999):";
cin>>num;
if (num>9999)
place=5;
else if (num>999)
place=4;
else if (num>99)
place=3;
else if (num>9)
place=2;
else place=1;
cout<<"place="<d*10000-thousand*1000)/100;
ten=(int)(num-ten_thousand*10000-thousand*1000-hundred*100)/10;
indiv=(int)(num-ten_thousand*10000-thousand*1000-hundred*100-ten*10);
cout<<"original order:";
switch(place)
{case
5:cout<en
dl;
cout<<"reverse order:";
cout<dred<<","<out<
using namespace std;
int main ()
{ long i; //i为利润
float bonus,bon1,bon2,bon4,bon6,bon10;
bon1=100000*0.1; //利润为10万元时的奖金
bon2=bon1+100000*0.075; //利润为20万元时的奖金
bon4=bon2+100000*0.05; //利润为40万元时的奖金
bon6=bon4+100000*0.03; //利润为60万元时的奖金
bon10=bon6+400000*0.015; //利润为100万元时的奖金
cout<<"enter i:";
cin>>i;
if (i<=100000)
bonus=i*0.1; //利润在10万元以内按10%提成奖金
else if (i<=200000)
bonus=bon1+(i-100000)*0.075; //利润在10万元至20万时的奖金
else if (i<=400000)
bonus=bon2+(i-200000)*0.05; //利润在20万元至40万时的奖金
else if (i<=600000)
bonus=bon4+(i-400000)*0.03; //利润在40万元至60万时的奖金
else if (i<=1000000)
bonus=bon6+(i-600000)*0.015; //利润在60万元至100万时的奖金
else
bonus=bon10+(i-1000000)*001; //利润在100万元以上时的奖金
cout<<"bonus="<
using namespace std;
int main ()
{long i;
float bonus,bon1,bon2,bon4,bon6,bon10;
int c;
bon1=100000*0.1;
bon2=bon1+100000*0.075;
bon4=bon2+200000*0.05;
bon6=bon4+200000*0.03;
bon10=bon6+400000*0.015;
cout<<"enter i:";
cin>>i;
c=i/100000;
if (c>10) c=10;
switch(c)
{case 0: bonus=i*0.1; break;
case 1: bonus=bon1+(i-100000)*0.075; break;
case 2:
case 3: bonus=bon2+(i-200000)*0.05;break;
case 4:
case 5: bonus=bon4+(i-400000)*0.03;break;
case 6:
case 7:
case 8:
case 9: bonus=bon6+(i-600000)*0.015; break;
case 10: bonus=bon10+(i-1000000)*0.01;
}
cout<<"bonus="<
using namespace std;
int main ()
{int t,a,b,c,d;
cout<<"enter four numbers:";
cin>>a>>b>>c>>d;
cout<<"a="<<<", "<
using namespace std;
int main ()
{int p,r,n,m,temp;
cout<<"please enter two positive integer numbers n,m:";
cin>>n>>m;
if (n }
p=n*m; //先将n和m的乘积保存在p中, 以便求最小公倍数时用
while (m!=0) //求n和m的最大公约数
{r=n%m;
n=m;
m=r;
}
cout<<"HCF="<='a' && c<='z'||c>='A' && c<='Z')
letters++;
else if (c==' ')
space++;
else if (c>='0' && c<='9')
digit++;
else
other++;
}
cout<<"letter:"<
using namespace std;
int main ()
{int a,n,i=1,sn=0,tn=0;
cout<<"a,n=:";
cin>>a>>n;
while (i<=n)
{tn=tn+a; //赋值后的tn为i个a组成数的值
sn=sn+tn; //赋值后的sn为多项式前i项之和
a=a*10;
++i;
}
cout<<"a+aa+aaa+...="<
using namespace std;
int main ()
{float s=0,t=1;
int n;
for (n=1;n<=20;n++)
{
t=t*n; // 求n!
s=s+t; // 将各项累加
}
cout<<"1!+2!+...+20!="<endl;
return 0;
}

3.19题
#include
using namespace std;
int main ()
{int i,j,k,n;
cout<<"narcissus numbers are:"<}
cout<
using namespace std;
int main()
{const int m=1000; // 定义寻找范围
int k1,k2,k3,k4,k5,k6,k7,k8,k9,k10;
int i,a,n,s;
for (a=2;a<=m;a++) // a是2~1000之间的整数，检查它是否为完数
{n=0; // n用来累计a的因子的个数
s=a; // s用来存放尚未求出的因子之和，开始时等于a
for (i=1;ieak; // 找出的笫1个因子赋给k1
case 2:
k2=i; break; // 找出的笫2个因子赋给k2
case 3:
k3=i; break; // 找出的笫3个因子赋给k3
case 4:
k4=i; break; // 找出的笫4个因子赋给k4
case 5:
k5=i; break; // 找出的笫5个因子赋给k5
case 6:
k6=i; break; // 找出的笫6个因子赋给k6
case 7:
k7=i; break; // 找出的笫7个因子赋给k7
case 8:
k8=i; break; // 找出的笫8个因子赋给k8
case 9:
k9=i; break; // 找出的笫9个因子赋给k9
case 10:
k10=i; break; // 找出的笫10个因子赋给k10
}
}
if (s==0) // s=0表示全部因子都已找到了
{cout<1) cout<1表示a至少有2个因子
if (n>2) cout<<","<2表示至少有3个因子，故应再输出一个因子
if (n>3) cout<<","<3表示至少有4个因子，故应再输出一个因子
if (n>4) cout<<","<5) cout<<","<
if (n>6) cout<<","<7) cout<<","<8) cout<<","<9) cout<<","<
using namespace std;
int main()
{int m,s,i;
for (m=2;m<1000;m++)
{s=0;
for (i=1;include
using namespace std;
int main()
{int k[11];
int i,a,n,s;
for (a=2;a<=1000;a++)
{n=0;
s=a;
for (i=1;i数"<
using namespace std;
int main()
{int i,t,n=20;
double a=2,b=1,s=0;
for (i=1;i<=n;i++)
{s=s+a/b;
t=a;
a=a+b; // 将前一项分子与分母之和作为下一项的分子
b=t; // 将前一项的分子作为下一项的分母
}
cout<<"sum="<
using namespace std;
int main()
{int day,x1,x2;
day=9;
x2=1;
while(day>0)
{x1=(x2+1)*2; // 第1天的桃子数是第2天桃子数加1后的2倍
x2=x1;
day--;
}
cout<<"total="<
#include
using namespace std;
int main()
{float a,x0,x1;
cout<<"enter a positive number:";
cin>>a; // 输入a的值
x0=a/2;
x1=(x0+a/x0)/2;
do
{x0=x1;
x1=(x0+a/x0)/2;
}
while(fabs(x0-x1)>=1e-5);
cout<<"The square root of "<
using namespace std;
int main()
{int i,k;
for (i=0;i<=3;i++) // 输出上面4行*号
{for (k=0;k<=2*i;k++)
cout<<"*"; // 输出*号
cout<lude
using namespace std;
int main()
{char i,j,k; /* i是a的对手;j是b的对手;k是c的对手*/
for (i='X';i<='Z';i++)
for (j='X';j<='Z';j++)
if (i!=j)
for (k='X';k<='Z';k++)
if (i!=k && j!=k)
if (i!='X' && k!='X' && k!='Z')