1、完整word)遗传算法(C++版)
#include
2、ble[10][10] = { {0,1,1272,2567,1653,2097,1425,1177,3947,1}, {1,0,1,2511,1633,2077,1369,1157,3961,1518}, {1272,1,0,1,380,1490,821,856,3660,385}, {2567,2511,1,0,1,2335,1562,2165,3995,933}, {1653,1633,380,1,0,1,1041,1135,3870,456}, {2097,2077,1490,2335,1,0,1,92
3、0,2170,1920}, {1425,1369,821,1562,1041,1,0,1,4290,626}, {1177,1157,856,2165,1135,920,1,0,1,1290}, {3947,3961,3660,3995,3870,2170,4290,1,0,1}, {1,1518,385,993,456,1920,626,1290,1,0} }; class Unit { public: int path[city_num];//个体的路径信息 int length;//个体价值 };
4、 class Group { public: Unit group[unit_num]; Unit best; int best_gen; Group() { best.length = 0x3f3f3f3f; best_gen = 0; for(int i = 0; i 〈 unit_num; i++) { bool flag[city_num] = {}; for(int j = 0; j 〈 city
5、num; j++) { int t_city = rand()%city_num; while(flag[t_city]) t_city = rand()%city_num; flag[t_city] = true; group[i].path[j] = t_city; } } } //对每个个体进行评估 void
6、 assess() { for(int k = 0; k < unit_num; k++) { int rel = 0; for(int i = 1; i 〈 city_num; i++) rel += length_table[group[k].path[i—1]][group[k]。path[i]]; rel += length_table[group[k]。path[city_num—1]][group[k]。path[0]];
7、 group[k].length = rel; } } //根据评估结果对个体进行排序 void unit_sort() { for(int i = 0; i < unit_num; i++) { for(int j = i+1; j < unit_num; j++) { if(group[i]。length > group[j]。length) {
8、 Unit temp; memcpy(&temp, &group[i], sizeof(Unit)); memcpy(&group[i], &group[j], sizeof(Unit)); memcpy(&group[j], &temp, sizeof(Unit)); } } } } //交叉 Unit cross(Unit
9、 &father, Unit &mother) { int l = rand()%city_num; int r = rand()%city_num; if(l > r) swap(l, r); bool flag[city_num] = {}; for(int i = l; i 〈= r; i++) flag[father。path[i]] = true; Unit son; int pos = 0
10、 for(int i = 0; i 〈 l; i++) { while(flag[mother.path[pos]]) pos++; son.path[i] = mother。path[pos++]; } for(int i = l; i <= r; i++) son。path[i] = father.path[i]; for(int i = r+1; i < city_num; i++)
11、 { while(flag[mother.path[pos]]) pos++; son。path[i] = mother。path[pos++]; } return son; } //突变 void mutation(Unit &t) { int proport = rand() % 100; if(proport 〉 ps) return;
12、 int one = rand()%city_num; int two = rand()%city_num; while(two != one) two = rand()%city_num; swap(t。path[one], t.path[two]); } //输出信息 void print() { for(int i = 0; i 〈 unit_num; i++) { printf("第%d
13、个个体,路径信息:”, i); for(int j = 0; j 〈 city_num; j++) printf(”%d ”, group[i].path[j]); printf(”;总权值:%d;\n”, group[i].length); } printf(”最优个体,路径信息:”); for(int j = 0; j < city_num; j++) printf("%d ", group[0].path[j]);
14、 printf(";总权值:%d;\n”, group[0]。length); } //种群进化 void work() { for(int i = 0; i < genmax; i++) { //如果进化层数大于20,加大变异的概率 if(i > 20) ps *= 3; assess();//评估 unit_sort();//根据评估结果排序
15、 if(best.length > group[0].length) { memcpy(&best, &group[0], sizeof(group[0])); best_gen = i; } for(int j = 0; j+2 < unit_num; j+=3) group[j+2] = cross(group[j], group[j+1]); for(int
16、 j = 0; j 〈 city_num; j++)//变异(从1开始,保留最优) mutation(group[j]); } } }; Unit group[unit_num];//种群变量 Unit bestone;//记录最短路径 int generation_num;//记录当前达到了第几代 int main() { srand((int)time(0)); for(int i = 0; i < 20; i++) { Group g; g。work(); printf("第%d次求解。路径:", i+1); for(int j = 0; j 〈 city_num; j++) printf("%d ”, g。best.path[j]); printf(”;总权值:%d; 第%d代;\n”, g.best.length, g.best_gen); } return 0; }






