心理统计学习题.ppt

单击此处编辑母版标题样式,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,心理统计学习题课,第二章 统计图表,1.,统计分组应注意哪些问题？,分组要以被研究对象的本质特性为基础,分类标志要明确，要包括所有数据,如删除过失所造成的变异数据，要遵循,3,原则,2.,直条图适合哪种资料？,条形图也叫做直条图，主要用于表示离散型数据资料，即计数资料。,3.,圆形图适合哪种资料,又称饼图，主要用于描述间断性资料，目的是为显示各部分在整体中所占的比重大小，以及各部分之间的比较，显示的资料多以相对数（如百分数）为主。,4.,将下列的反应时测定资料编制成次数分布表、累积次数分布表、直方图次数多边形。,177.5 167.4 116.7 130.9 199.1 198.3 225.0 212.0 180.0 171.0 144.0 138.0 191.0 171.5 147.0 172.0 195.5 190.0 206.7 153.2 217.0 179.2 242.2 212.8 171.0 241.0 176.5 165.4 201.0 145.5 163.0 178.0 162.0 188.1 176.5 172.2 215.0 177.9 180.5 193.0 190.5 167.3 170.5 189.5 180.1 217.0 186.3 180.0 182.5 171.0 147.0 160.5 153.2 157.5 143.5 148.5 146.4 150.5 177.1 200.1 137.5 143.7 179.5 185.5 181.6,最大值,242.2,最小值,116.7,全距为,125.5,N=65,代入公式,K=1.87,（,N-1,）,2/5=9.8,所以,K,取,10,定组距,13,最低组的下限取,115,表,2-1,次数分布表,分组区间,组中值（,Xc,）,次数（,f,）,频率（,P,）,百分次数（,%,）,232,238,2,0.03,3,219,225,1,0.02,2,206,212,6,0.09,9,193,199,6,0.09,9,180,186,14,0.22,22,167,173,16,0.25,25,154,160,5,0.08,8,141,147,11,0.17,17,128,134,3,0.05,5,115,121,1,0.02,2,合计,65,1.00,100,表,2-2,累加次数分布表,分组区间,次数（,f,）,向上累加次数,向下累加次数,实际累加次数（,cf,）,相对累加次数,实际累加次数（,cf,）,相对累加次数,232,2,65,1.00,2,0.03,219,1,63,0.97,3,0.05,206,6,62,0.95,9,0.14,193,6,56,0.86,15,0.23,180,14,50,0.77,29,0.45,167,16,36,0.55,45,0.69,154,5,20,0.31,50,0.77,141,11,15,0.23,61,0.94,128,3,4,0.06,64,0.98,115,1,1,0.02,65,1.00,第三章 集中量数,3.,对于下列数据，使用何种集中量数表示集中趋势其代表性更好？并计算它们的值。,4 5 6 6 7 29,中数,=6,3 4 5 5 7 5,众数,=5,2 3 5 6 7 8 9,平均数,=5.71,4.,解：组中值由“精确上下限”算得；设估计平均值在,35,组；中数所在组为,35,，,f,MD,=34,其精确下限,Lb=34.5,，该组以下各组次数累加为,Fb,=21+16+11+9+7=64,分组,f,组中值,65,1,67,60,4,62,55,6,57,50,8,52,45,16,47,40,24,42,35,34,37,30,21,32,25,16,27,20,11,22,15,9,17,10,7,12,N=157,M=36.14,5.,求下列四个年级的总平均成绩。,年级,一,二,三,四,90.5,91,92,94,n,236,318,215,200,解：,6.,三个不同被试对某词的联想速度如下表，求平均联想速度,被试,联想词数,时间（分）,词数,/,分（,Xi,）,A,13,2,13/2,B,13,3,13/3,C,13,2.5,13/2.5,解：,7.,下面是某校几年来毕业生的人数，问平均增加率是多少？并估计,10,年后的毕业人数有多少。,年份,1978,1979,1980,1981,1982,1983,1984,1985,毕业人数,542,601,750,760,810,930,1050,1120,解：用几何平均数变式计算：,所以平均增加率为,11%,10,年后毕业人数为,112,01.10925,10,=3159,人,第四章 差异量数,5.,计算下列数据的标准差与平均差,11.0 13.0 10.0 9.0 11.5 12.2 13.1 9.7 10.5,S=1.37,7画线实验,CV1=(s1/)100%=(0.7/1.3)100%=53.85%,CV2=(s2/)100%=(1.2/4.3)100%=27.91%CV1,所以标准线为,5cm,的离散程度大。,即各班成绩的总标准差是,6.03,8.,9.,第五章 相关关系,5.,欲考查甲乙丙丁四人对十件工艺美术品的等级评定是否具有一致性，用哪种相关方法？,等级相关（肯德尔和谐系数、,w,系数）,被试,A,B,A,2,B,2,AB,R,A,R,B,R,A,R,B,D=R,A,-R,B,D,2,1,86,83,7396,6889,7138,2,3,6,-1,1,2,58,52,3364,2704,3016,78,56,-1,1,3,79,89,6241,7921,7031,4,1,4,3,9,4,64,78,4096,6084,4992,6,4,24,2,4,5,91,85,8281,7225,7735,1,2,2,-1,1,6,48,68,2304,4624,3264,9,6,54,3,9,7,55,47,3025,2209,2585,8,9,72,-1,1,8,82,76,6724,5776,6232,3,5,15,-2,4,9,32,25,1024,625,800,10,10,100,0,0,10,75,56,5625,3136,4200,5,7,35,-2,4,670,659,4808047193,46993,55,55,368,34,6.,下表是平时两次考试成绩分数，假设其分布成正态，分别用积差相关与等级相关方法计算相关系数，并回答，就这份资料用哪种相关法更恰当？,6.,被试,X,Y,R,X,R,Y,D=R,X,-R,Y,D,2,1,13,14,1,1,0,0,2,12,11,2,3,-1,1,3,10,11,3.5,3,0.5,0.25,4,10,11,3.5,3,0.5,0.25,5,8,7,5,5.5,-0.5,0.25,6,6,7,6.5,5.5,1,1,7,6,5,6.5,7,-0.5,0.25,8,5,4,8.5,9,-0.5,0.25,9,5,4,8.5,90.5,0.25,10,2,4,10,9,1,1,N=10,4.5,7.,被试,性别,成绩,男成绩,女成绩,成绩的平方,1,男,83,83,6889,2,女,91,91,8281,3,女,95,95,9025,4,男,84,84,7056,5,女,89,89,7921,6,男,87,87,7569,7,男,86,86,7396,8,男,85,85,7225,9,女,88,88,7744,10,女,92,92,8464,880,425,455,77570,适用点二列相关计算法。,p,为男生成绩，,q,为女生成绩，,为男生的平均成绩，,为女生的平均成绩，,为所有学生成绩的标准差,从表中可以计算得：,p=0.5 q=0.5,8.,9.,被试,成绩,A,成绩,B,1,及格,83,2,不及格,91,3,及格,95,4,不及格,84,5,及格,89,6,不及格,87,7,及格,86,8,不及格,85,9,及格,88,10,不及格,92,880,查正态表得,11.,被评价者,被试,R,i,R,i,2,1,2,3,4,5,6,7,8,9,A,1,1,1,1,1,1,1,1,1,9,81,B,2,4,3,3,9,4,3,3,2,33,1089,C,4,2,4,4,2,9,5,5,8,43,1849,D,3,5,5,5,5,2,10,7,4,46,2116,E,9,6,2,2,6,5,2,6,9,47,2209,F,6,7,8,6,3,6,6,4,6,52,2704,G,5,3,9,10,4,7,9,8,3,58,3364,H,8,10,6,8,8,3,7,10,7,67,4489,I,7,8,10,7,10,10,8,2,5,67,4489,J,10,9,7,9,7,8,4,9,10,73,5329,495,27719,12.,A,B,C,D,E,F,G,H,I,J,A,9,9,9,9,9,9,9,9,9,B,0,7,7,5,8,7,7,8,8,C,0,2,6,5,6,7,7,7,7,D,0,2,3,5,6,5,8,7,8,E,0,4,4,4,5,5,6,6,9,F,0,1,3,3,4,6,7,7,7,G,0,2,2,4,4,3,5,6,6,H,0,2,2,1,3,2,4,4,5,I,0,1,2,2,3,2,3,5,5,J,0,1,2,1,0,2,3,4,4,一家广告代理商想了解一家公司产品质量等级是否与其商场份额等级有关。小规模的实验研究，获得该行业,12,家公司的质量等级。,作业,公司的质量形象与其市场份额等级成,正相关,。,学生,n=6,评价者,K=4,1,2,3,4,1,3,4,2,1,2,4,3,1,3,3,2,1,3,4,4,6,5,6,5,5,1,2,4,2,6,5,6,5,6,例：,4,位教师对,6,位学生作文竞赛的名次排列次序如表,6,。问,4,位教师评定的一致性程度如何,？,表,6 4,位教师对,6,位学生作文竞赛的名次排列,练习,2014,心理学考研真题,49,欲比较同一团体不同观测值的离散程度，最合适的指标是（）,A,。全距,B,。方差,C,。四分位距,D,。差异系数,50,现有,8,位面试官对,25,名求职者的面试表现作等级评定。为了解这,8,位面试官评定的一致性程度，最适宜的统计方法是计算（）,A,。斯皮尔曼相关系数,B,。积差相关系数,C,。肯德尔和谐系数,D,。点二列相关系数,9,选择总体参数的点估计，依据的标准是（）,A,。无偏性,B,。变异性,C,。有效性,D,。一致性,PPT,模板下载：,you,