降次解一元二次方程——因式分解法教学.ppt

单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,单击此处编辑母版标题样式,降次解一元二次方程-,因式分解法,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,侗刽师报鳃骄桑僳释恩垣伺贬侧歼蹄形缝喘啄刨拴钩委坟凹簿坤灭腰桌硒降次解一元二次方程因式分解法教学课件4zubDN,1,2021,解：原方程可变形为,(x+2)(x,2)=0,X,+,2,=0或 x,2,=0,x,1,=-2,x,2,=2,X,2,4=0,一移项,二分解,三降次,四求解,探索新知,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,蔑业理控禾麓修嚼妄匪酪绰荫殷颓犊淄敦氦皋特远禄憾狂作季屈萄秸中佯降次解一元二次方程因式分解法教学课件4zubDN,2,快速回答：下列各方程的根分别是多少？,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,籍附苗蹭斡惋若迂芹敏辣搬圆溢溯坛通跃产蛙匣搁奇绢辱挚胞廉匆考揖爆降次解一元二次方程因式分解法教学课件4zubDN,3,例1、解下列方程,1、x,2,3x,10=0 2、(x+3)(x,1)=5,解：原方程可变形为 解：原方程可变形为,(x,5)(x+2)=0 x,2,+2x,8=0,x,5=0或x+2=0 (x,2)(x+4)=0,x,1,=5,x,2,=-2 x,2=0或x+4=0,x,1,=2,x,2,=-4,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,言骋自妮玉钞指幢啸跌四堕砷冈剖瓮龚闸绅谣咕涟壹厄来妙藩了靠哟钧呈降次解一元二次方程因式分解法教学课件4zubDN,4,例2、解下列方程,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,弛郁吉披珐嗣铡月抢德著划晌煽州驶埂彻阑沤搜嫂璃哪酪趣彦茂肩癸麓霸降次解一元二次方程因式分解法教学课件4zubDN5,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,榔跌暂志巷耸淮套止允避滦镊辙便淹末剩兆麻羌哈堡耀边掖徽年哲俐探酣降次解一元二次方程因式分解法教学课件4zubDN,6,(2)(3x+1),2,5=0,解：原方程可变形为,(3x+1+,)(3x+1,)=0,3x+1+,=0或3x+1,=0,x,1,=,x,2,=,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,按盏裴赡挟益刻孪差扰眼氟囚辰端不悲嘴摧抢拔喇涕课恩蒸梭鼓褒奢攘嘎降次解一元二次方程因式分解法教学课件4zubDN,7,1.方程右边不为零的化为,。,零,一次因式,有一个,一元一次方程的解,用因式分解法解一元二次方程的步骤:,4.两个,就是原方程,的解。,3.至少,一次因式为零，得,到两个一元一次方程。,2.将方程左边分解成两个_,的乘积。,课堂小结,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,客斌株艰地肩溅灰豺碳奸苞门藤素岳靠浑蛮丧惦铆姿惶剩为杖拒篓恐充灿降次解一元二次方程因式分解法教学课件4zubDN,8,三、巩固练习,课本P40练习1,课堂,训练,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,匙谈纶可够韭袱鬼呢蹈陌钳在鞋谤瓦亥铂箔罢畔势聂洱皖耽耕痒滓今虾兰降次解一元二次方程因式分解法教学课件4zubDN,9,1.用因式分解法解关于 的方程,四、课堂延伸,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,止恼躺柑脐坊三榜罢录伊驼棒抡悟垮瑰岸欧莉转搬何匈烟炮碳管涅祁洲提降次解一元二次方程因式分解法教学课件4zubDN,10,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,其潮脂文浦蹋拇桑吗勘秀辆府迪邪喂陈央旋摆茬凛轨狸越窥臃灭洪诛追魄降次解一元二次方程因式分解法教学课件4zubDN,11,解：原方程可变形为：,(xa+b)(xab)=0,xa+b=0 或 xab=0,x,1,=abx,2,=a+b,(xa),2,b,2,=0,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,兴瞻抉雇殃揣弘睬兔切雾匡隐模北身筏央曳昆谗穿等莆淘驰失绳搏幻酱赁降次解一元二次方程因式分解法教学课件4zubDN,12,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,都臃趾判沼琉思怂沥纪尝但鲤顽咋舔锰诊爬攀白虱申奸里战欲飘店勋澎启降次解一元二次方程因式分解法教学课件4zubDN,13,右化零左分解,两因式各求解,简记歌诀,：,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,阎径抉诈捏卵舰蜜劈姜辞孜造绥娜源瓣鸡括勒燥玄氓协淮浦绿稳邱荚侗迁降次解一元二次方程因式分解法教学课件4zubDN,14,六、作业设计,课本P43,习题22.2第6题,作业,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,境绵椭督浅僧橇讫徘平纸艰隆冗刨天幻真腮东谚眠拉很漏繁锁莽渝锋中牺降次解一元二次方程因式分解法教学课件4zubDN,15,谢谢!,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,管寞氧难瞄烤霖娥增勉汕晌钞脊唬坎谚奄粟技残屑诈弱塔博姚火注层枪杆降次解一元二次方程因式分解法教学课件4zubDN,16,2021,