多哈地下大厅穿孔遮阳蓬计算书-081112-en.doc

High Rise Office Building，Doha，Qatar Calculation Sheet for the Facade

Calculation Sheet for Canopy of Undergroud Lobby
-Doha High Rise Office Building

King Glass Engineering Group

Calculated by： Checked by： Approved by：

Architectural: Structural:

This calculation sheets should be read in conjunction with the related drawings.

1. Calculation of Perforated Al Sheet
The perforated Al sheet at the outermost of the canopy is the most critical one in press bearing and calculation is required. Relevant sketches are as follows:
Figure 1-1 Perforated Al Sheet Plan

Figure 1-2 Section A-A

Figure 1-3 Section B-B

Figure 1-4 Sample C

Figure 1-5 Sample D

Figure 1-6 Sample E

1.1 Calculation of Supporting Frame and Rinforcement Bar of Al Sheet
1.1.1 Design Sketch
Figure 1-6 Supporting Frame and Reiforcement Bar

The ‘▽’in the sketch symbolizes hinged connection.
Section of frame is as follows:

Figure 1-7 Frame Section
Section data of reinforcement bar is as follows:

Figure 1-8 Sectional Data of Reinforcement Bar

1.1.2 Standard Load
1.1.2.1 Standard Windload
This project is 100m from the coastline, which ground surface roughness is sorted as “Village”.
Building-type factor: Kb=2。（BS6399 part2-1.6.1 table 1）
Building height: H=1.3m<300m,
Cr<0.25,( BS6399 part2-1.6.1 table 1)
Effective height: He=1.3m
According to Section 2.2.2, part 5 of tender document for Doha High Rise Office Building, the basic wind speed Vb is 25m/s.
Site windspeed: Vs=Vb×Sa×Sd×Ss×Sp (BS6399-part 2-2.2.2)
Sa=1+0.001△s (BS6399-part 2-3.2.2)
In which：
In which：
Vb Basic wind speed.
Sa Height factor
Sd Direction factor (Ref. BS6399, Clause2.2.2.3, Volume 2.)
Ss Season factor (Ref. BS6399, Clause2.2.2.4, Volume 2.)
Sp Propability factor (Ref. BS6399, Clause2.2.2.5, Volume 2.)
△s is the altitude of site ground surface.
△s=2m, So, Sa=1+0.001x2=1.002
Sd =1.0，Ss =1.0 ，Sp =1.0
∴ Vs=Vb×Sa×Sd×Ss×Sp=25x1.002x1.0x1.0x1.0x1.0=25.05m/s
Equivalent wind speed is：
Ve=Vs×Sb (BS6399 Part-3.2.3.1, Division 2)
Sb= Sc{1+（gtxSt）+Sh} (BS6399 Part-3.2.3.2.2, Division 2)
In which：
Sb Factor of topography and building.
Sc Wind field factor (Ref. BS6399 table 22, Division 2)
St Onflow adjustment factor(Ref. BS6399 table 22, Division 2)
gt Gust peak factor (Ref. BS6399 clause 3.2.3.3, Division 2)
Sh Topography increment (Ref. BS6399 clause 3.2.3.4, Division 2)

∵:
Sc=0.873（effective height He=1.3m）; St=0.203（effective height He=1.3m）;
gt =3.44; Sh=0
∴：Sb= Sc{1+（gtxSt）+Sh}= 0.873x{1+（3.44x0.203）+0}=1.483
Effective wind speed at 1.3m:
Ve=Vs×Sb=25.05x 1.483=37.15m/s
Dynamic press is：
q=0.613Ve2=0.613x(37.15)2=846N/m2=0.846KN/m2 (BS6399, Part-3.1.2.1,Division 2)
static press p ：
p=qeCp （3.1.3.1.3 b ）
qe is dynamic press susdained by canopy or building members under effective wind speed. See 3.1.2；
Cp is the coefficient of static press on members. See 2.7.
qe =q=846N/m2
Cp=－2.0
p= qeCp=846X（－2.0）=1692 N/m2
Punching ratio of perforated Al sheet is 32.1%.
So the standard effective windload on Al sheet is:
(1-0.321)x1692=1149 N/m2（Attraction）

1.1.2.2 Standard Deadload
（1），Deadload of Perforated Al Sheet
Thickness of Al sheet is 3mm with punching ratio 32.1%. For the strength of material is decided by young’s modulus and moment of inertia,ie rigidness：EI, in which E is young’s modulus and I is moment of inertia. In this design, the sheet is uniform with holes laid out uniformly. So we can assume that the moment of inertia of the perforated sheet equals with Al sheet with the same dimension multiply (1-0.321). Again, for El is a fixed value, so we can use a equivalent mock-up, ie: Decrease E without changing I, the young’s modulus of the original sheet ‘E’=0.7x105N/mm2.So equivalent young’s modulus of perforated sheet ‘E1’ =0.7 x105 x(1-0.321)=0.4573 x105N/mm2.
The same，the equilavent compensation density of perforated sheet is:
2.8 x10-6x(1-0.321)=1.9 x10-6 kg/mm3
Deadload of perforated Al sheet is auto-calculated by ANSYS with gravity acceleration 9.8m/s2.

（2），Al Frame and Reinforcement Bar
Young’s modulus of frame and reinforcement bar E=0.7 x105 N/mm2。
Density: 2.8 x10-6 kg/mm3
Deadload of perforated Al sheet is auto-calculated by ANSYS with overall gravity acceleration 9.8m/s2.

1.1.3 Load Combination
Strength calculation：1.0deadload+1.2windload
Deflection calculation：1.0deadload+1.0windload
（BS8118-1　 3.2.3　　Table 3.1）

1.1.4 Strength Calculation
1.1.4.1 Design Load
In this design, unifromly distributed windload on the Al sheet is: 1.2x1.149x10-3=1.379 x10-3 N/mm2
Deadload of perforated Al sheet is auto-calculated by ANSYS with overall gravity acceleration 9.8m/s2.
Simulate frame and reinforcement bar with beam 188 of ANSYS, simulate perforated Al sheet with shell 163. Confine the movement of each support in Figure 1-5 in direction x, y and z. Calculate with the throry of minimum deflection.
1.1.4.2 Mock-up for Calculation
Mock-up for calculation is as follows:

Figure 1-9 Mock-up for Frame and Reiforcement Bar (Front View)

Figure 1-10 Mock-up for Frame and Reiforcement Bar (Back View)

1.1.4.3 Results of Strength Calculation
Stress bearing calculation is as bellows:

Figure 1-11 Stress bearing of Frame and Reiforcement Bar-Under Design Load
Grade of Al frame and reinforcement is 6063A-T5 with yield strength160 N/mm2.
Maximum stress is: 82.117N/mm2<160/γm＝160/1.2=133.3N/mm2
(γm material coefficient, see BS8118-part1-3.3.3 Table3.3)
Meet the requirement !

1.1.5  Deflection Calculation
1.0deadload+1.0windload
Deflection is as follows:

Figure 1-12 Deflection of Al Frame and Reinforcement Bar-Under Standard Load

Max.deflection is ：6.455mm<1355/100=13.55mm （BS8118－part1－3.4.1－table 3.4）
Meet the rquirements !

1.2 Calculation of Perforated Al Sheet
1.2.1 Design Sketch
Interval between two Al welding bolts should not less than 350mm. So design sketch of perforated Al sheet is:

Figure 1-13 Design Sketch of Al Sheet

1.2.2 Standard Load
1.2.2.1 Standard Windload
Standard effective windload on perforated Al sheet is:
(1-0.321)x1692=1149 N/m2（suction）
1.2.2.2 Standard Deadload
Thickness of Al sheet is 3mm with punching ratio 32.1%. For the strength of material is decided by young’s modulus and moment of inertia,ie rigidness：EI, in which E is young’s modulus and I is moment of inertia. In this design, the sheet is uniform with holes laid out uniformly. So we can assume that the moment of inertia of the perforated sheet equals with Al sheet with the same dimension multiply (1-0.321). Again, for El is a fixed value, so we can use a equivalent mock-up, ie: Decrease E without changing I, the young’s modulus of the original sheet ‘E’=0.7x105N/mm2.So equivalent young’s modulus of perforated sheet ‘E1’ =0.7 x105 x(1-0.321)=0.4573 x105N/mm2.
The same，the equilavent compensation density of perforated sheet is:

2.8 x10-6x(1-0.321)=1.9 x10-6 kg/mm3
Deadload of perforated Al sheet is auto-calculated by ANSYS with overall acceleration 9.8m/s2.

1.2.3 Load Combination
Strength calculation：1.0deadload+1.2windload
Deflection calculation：1.0 deadload+1.0windload
（BS8118-1　 3.2.3　　Table 3.1）

1.2.4 Strength Calculation
1.2.4.1 Design Load
In this design, uniformly distributed windload on Al sheet is:
1.2x1.149x10-3=1.379 x10-3 N/mm2
Deadload of perforated Al sheet is auto-calculated by ANSYS with overall acceleration 1.0x9.8m/s2.
Simulate perforated Al sheet with shell 163. Confine the movement of each support in Figure 1-13 in direction x, y and z. Calculate with the throry of minimum deflection.

1.2.4.2 Mock-up for Calculation
Mock-up for calculation is as follows:

Figure 1-14 Perforated Al Sheet Mock-up

1.2.4.3 Strength Calculation Result
Stress bearing calculation is as follows

Figure 1-15 Stres Bearing of Al Sheet-Under Design Load
Grade of Al sheet is 1200-H14 with yield strength 115 N/mm2.
Max. strength bearing is 80.551N/mm2<115/γm＝115/1.2=95.8N/mm2
(γm is material coefficient, see BS8118-part1-3.3.3 Table3.3)
Meet the requirements!

1.2.5  Deflection Calculation
Deflection calculation is 1.0deadload+1.0 windload.
Deflection calculation is as follows:

Figure 1-16 Deflection under Standard Design Load
Maximum deflection of Al sheet, frame and reinforcement bar is
6.455＋5.882＝12.337mm
12.337mm<1355/100=13.55mm （BS8118－part1－3.4.1－table 3.4）
Meet the requirements！

18