1、 悬臂式挡土墙计算书(一) 设计资料:1 悬臂式路肩挡土墙(如图)。墙高H=5.50 m,顶宽 b=0.25m,立壁面坡坡度1:m=1:0.05,基础埋深 h=0.5m。2 墙背填土容重 =18kN/m3,内摩擦角0=34。3 地基土内摩擦角0=35,摩擦系数 f=0.4,容许承载力=150kPa。4 活荷载为汽车-超20级。5 抗滑动和倾覆安全系数Kc=1.3,Ko=1.5。6 钢筋混凝土结构设计数据:1) 混凝土标号R=25Mpa,抗压设计强度Ra=8500kPa,弹性模量Eh=2.3*10 E7 kPa,抗拉设计强度Ri=1.05Mpa 。2) I级钢筋抗拉设计强度Rg=2.4x10E5
2、kPa,弹性模量 Eg=2.1x10E8kPa。3) 裂缝容许宽度fmax=0.2mm。(二) 土压力计算1 汽车荷载换算由表3-2-6中公式,有 h0= 200.00/13.0+0.577(H+2a) = 200.00/(18*(13+0.577*(5.5+2*0) =0.687m2用朗金公式计算土压力(=0) Ka=0.271 0=h0Ka =18*0.687*0.271 =3.351 Kpa H =(h0+H)Ka =18.0*(0.687+5.5)*0.271 =30.180 KPa由式(3-6-1)、(3-6-4)得全墙土压力E及力臂y为E=1/2H2Ka(1+2h0/H) =0.5
3、*18*5.5*5.5*0.271*(1+2*0.687/5.5) =92.211 kNy=(3h0+H)H/3(2h0+H) =2.017 m(三) 墙身尺寸计算1. 底板长度B假定底板厚度h3=0.5m,h1=h3=0.5 m ,则 H1=H-h3=5.5-0.5=5.0 m B2=b+mH1=0.25+0.05*5.0=0.50 m当18kN/m3,f=0.4 时,由表3-6-1得容重修正系数1.07由式(3-6-7)得踵板长度B3为B3= =1.30*92.211/(0.4*(5.5+0.687)*1.07*18)-0.5=2.015 m由式(3-6-9)得踵板的修正长度为B3=1/2
4、*mH1=0.5*0.05*5.0=0.125 m由式(3-6-10a) 得趾板长度为B1= =0.374取B1=0.90 m B3=2.40 m底板长度B=B1+B2+B3 =3.80 m2 立壁厚度立壁根部截面(Hi=H1=5.5 m)由式(3-6-15)得该截面的剪应力Q1为Q1=EXHi=Hicos(0.5Hi+h0)Ka =18*5.0*1*(0.5*5.0+0.687)*0.271 =77.73 kN由式3-6-16 该截面的弯矩M1为 M1=Mhi=1/6Hi2cos(Hi+3h0)Ka =1/6*18*5.02*1*(5.0+3*0.687)*0.271 =143.51 kN.
5、m根据桥规第4.1.2条,计算内力Q1j,M1j为Q1j=1.2Q1=1.2*77.73=93.28 kN M1j=1.2M1=1.2*143.51=172.22 kN.m1) 按配筋要求确定厚度取配筋率0.7%,由式(3-6-11a)和(3-6-11b)有 =Rg/Ra=0.007*2.4*100000/14500 =0.116 A0=(1-0.5)=0.116*(1-0.5*0.116)=0.109由式(3-6-11),截面有效厚度为 h0sqr(Mj*c)/(A0*b*Ra) =sqr(172.22*1.25)/(.109*1.0*14500) = 0.37 m2) 按斜裂缝限制要求确定
6、厚度由式(3-16-12),截面有效厚度为h0Qij/(0.05*sqrR*b) =93.28/(0.05*sqr(25)*100) =3.73 cm =0.05 m立壁厚度由配筋率控制,取 h0=0.37 m 保护层厚度为0.04m,则立壁厚度为 0.41 m (与原假设的B2=.50 相符)3 底板厚度作用于挡土墙基底的剪应力为: N=Kc*Ex/f =1.30*92.211/0.4=299.68 (kN)底板厚度由踵板控制,并假设地基反力近似地呈三角形分布 2=0 1=2N/B=2*299.68/3.80=157.723 (kN)踵根部截面(B3I=B3=2.40 m)由式(3-6-17
7、) 得该截面的剪应力为(=0, 2=0时)Q3=Q3I=B3I*(H1+h0)+ h*h3-0.5B3I*1/B)=2.40*(18*(5.0+0.687)+25*0.5-0.5*2.40*157.723/3.80)=156.140 kN由式(3-6-18)得该截面的弯矩为M3=M3I=B3I2/6*(3(H1+h0)+3h*h3-B3I*1/B)=2.402/6*(3*18*(5.0+0.687)+3*25*0.5-157.723*2.40/3.80)=235.183 kN.m根据桥规第4.1.2条,计算内力Q1j,M1j为Q1j=1.2Q1=1.2*156.14=187.368 kN M1
8、j=1.2M1=1.2*235.183=282.220 kN.m3) 按配筋要求确定厚度取配筋率0.7%,由式(3-6-11a)和(3-6-11b)有 =Rg/Ra=0.007*2.4*100000/14500 =0.116 A0=(1-0.5)=0.116*(1-0.5*0.116)=0.109由式(3-6-11),截面有效厚度为 h0sqr(Mj*c)/(A0*b*Ra) =sqr(282.220*1.25)/(0.109*1.0*14500) = 0.47 m4) 按斜裂缝限制要求确定厚度由式(3-16-12),截面有效厚度为h0Qij/(0.05*sqrR*b) =187.368/(0
9、.05*sqr(25)*100) =7.49 cm =0.08 m立壁厚度由配筋率控制,取 h0=0.47 m 保护层厚度为0.04m,则立壁厚度为 0.51 m (与原假设的h3=0.50 基本相符)(四) 墙体稳定性和基底应力验算1. 求全墙总竖向力N和抗倾覆力矩My (1)踵板上填土重W及力臂Zw(对趾板端部的力臂) W=B3(H1+h0)=18*2.40*(5.0+0.687)= 245.678 kN Zw=B1+B2+B3/2=0.9+0.50+0.5*2.40=2.60 m (2)墙体自重G及力臂Zga. 立壁自重Wa及力臂ZaWa=1/2*h*H1*(B2+b)=1/2*25*5
10、.0*(0.50+0.25)=46.875 kNZa=(b2+b*B2+B22)/(3*(b+B2)+(B2+2b)(B2-b)/(3(b+B2)+B1=1.206 mb. 趾板、夹块和踵板的自重Wb及力臂ZbWb=h*B2*h3=25*0.5*.50=6.25 kNZb=B1+B2/2=0.8+0.5/2=1.15 mWc=h*B1*h01 =25*0.9*0.5 =11.25 kNZc=B1/2 =0.45 mWd=h*B3*h3 =25*2.40*0.5 =30 kNZd=B1+B2+B3/2 =0.8+0.5+2.4/2 =2.6 m G=Wa+Wb+Wc+Wd=94.375 kN Z
11、g=(Wa*Za+Wb*Zb+Wc*Zc+Wd*Zd)/G =1.555 m(3)趾板上覆土重Wh及力臂Zh Wh=(h-h01)*B1* =(1.0-0.5)*0.9*18 =8.1 kN Zh=1/2B1=0.45 m全墙总竖向力及抗倾覆力矩为 N=W+G+Wh=245.678+94.375+8.10=348.153 kN My=W*Zw+G*Zg+Wh*Zh =245.678*2.6+94.375*1.555+8.1*0.45 =789.168 kN.m2. 验算抗滑动稳定系数Kc=N*f/Ex =348.153*0.4/92.208 =1.510 1.3 (满足要求)3. 验算抗倾覆稳
12、定系数倾覆力矩M0为 M0=Ex*y=92.208*2.017=185.942 kN.m K0=My/M0 =789.168/185.942 =4.244 1.50 (满足要求) 4. 验算偏心距 Zn=(My-M0)/N =(786.168-185.942)/348.153=1.733 m B/6=3.80/6= 0.633 m E=B/2-Zn=3.80/2-1.733=0.167 B/6 (满足要求)5. 验算基底应力 1,2=N/B(16e/B)=348.153/3.80*(16*0.167/3.80)=115.829 kPa = 67.410 kPa =120 kPa(五) 墙身配筋
13、或裂缝开展宽度计算1 内力计算 各截面内力值构件截面Qi (kN)Mi (kN.m) Qij (kN)Mij (kN.m)立壁a-a16.45813.20619.74915.847b-b52.42778.83862.91294.606c-c77.728143.50993.274172.211趾板d-d79.39536.65595.68243.986踵板e-e77.198107.31792.638128.780f- f41.08521.60449.30225.925 注:Qij , Mij 为按桥规第4.1.2条换算的截面计算内力。2. 配筋计算 各截面配筋计算表构件截面 Mij (kN.m)h
14、0(m)A0 (%)Ag(cm2)选用钢筋立壁a-a15.8470.310.0140.01430.092.681716b-b94.6060.410.050.050.3012.3251416c-c172.2110.460.070.07280.4420.2351416趾板d-d43.9860.460.0180.0180.115.026716踵板e-e128.7800.460.0520.0540.32614.985916f- f25.9250.460.0110.0110.0642.959163. 裂缝开展宽度计算 各截面裂缝宽度值构件截面 Mi (kN.m)h0(m) (%) d (mm) (kPa
15、)fmax(mm)立壁a-a13.2060.310.4541634790.210.041b-b78.8380.410.6871678519.370.085c-c143.5090.460.61116127392.810.141趾板d-d36.6550.460.3061665077.260.08踵板e-e107.3170.460.39316148189.880.175f- f21.6040.460.3931618235.450.022 由上表可知,各截面最大裂缝开展宽度均小于0.2mm,满足要求。4. 斜截面抗剪强度验算根据桥规第4.1.13条,如截面受弯构件满足以下要求时,则不需进行斜截面抗剪强
16、度计算,且按构造要求配置箍筋;Qj0.038Rt *b *h0 各截面满足抗剪强度情况构件截面h0(cm)0.038Rt b h0 Qij (kN)立壁a-a31182.5919.749b-b41241.1562.912c-c46270.9493.274趾板d-d46270.9495.682踵板e-e46270.9492.638f- f46270.9449.302 由上表可知,各截面仅需按构造要求配置箍筋。0万U豆体验卡卡号:50D890668267e3349e33密码:686d03401eefba96faba奖品名称:500万U豆体验卡卡号:50De7a00c543af387fc0密码:b2
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