指数不等式和对数不等式解法复习课程.ppt

单击此处编辑母版标题样式,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,指数、对数,不等式的解法,河南省泌阳县职业教育中心,周祥松,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,指数不等式的解法,是利用指数函数的性质化为同解的代数不等式,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,对数不等式的解法a1时,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,对数不等式的解法（0a1）时,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,例1：解不等式：,解,(1)原不等式,所以原不等式的解集为,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,例2,解,所以原不等式的解集为：,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,例3,解：原不等式,所以原不等式的解集为：,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,例4,解不等式,解:原不等式可化为：,原不等式的解集为,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,例5求 的定义域,解：要使此函数有意义：只须,原不等式的解集为,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,例2：袋中有5个白球和3个黑球，从中任取两个球，求取得的,两个球颜色相同的概率。,解：设A=两球颜色相同,B=两白球,C=两黑球 A=B+C其中B、C互斥,P（A）=P（B+C）=P（B）+P（C）,答：取得两球,颜色相同的概率,是0,464,再见,Evaluation only.,Created with Aspose.Slides for.NET 3.5 Client Profile 5.2.0.0.,Copyright 2004-2011 Aspose Pty Ltd.,